return ax from scatter for external usage #253
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M-R-Schaefer
reviewed
Jan 4, 2024
| idx = z.argsort() | ||
| x, y, z = x[idx], y[idx], z[idx] | ||
| ax.scatter(x, y, c=z, **kwargs) | ||
| return ax.scatter(x, y, c=z, **kwargs) |
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shouldn't this return ax itself?
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I thought I need this change, but I found another solution. There is probably a better way to make this function more user friendly, but we can also close.
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I don't mind either way
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