[lab-mysql-select]LuísaFreitas

your-code/solutions.sql

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+USE publications;
+
+-- Challenge 1 - Who Have Published What At Where?
+
+CREATE VIEW all_publications AS
+SELECT titleauthor.au_id AS author_id, authors.au_lname AS last_name , authors.au_fname AS first_name, title, publishers.pub_name AS publisher
+FROM titleauthor 
+LEFT JOIN authors ON titleauthor.au_id = authors.au_id
+LEFT JOIN titles ON titleauthor.title_id = titles.title_id
+LEFT JOIN publishers  ON titles.pub_id = publishers.pub_id;
+
+SELECT * FROM all_publications;
+
+-- Challenge 2 - Who Have Published How Many At Where?
+
+SELECT author_id, last_name , first_name, publisher, COUNT(title)
+FROM all_publications
+GROUP BY 1,2,4
+ORDER BY 5 DESC;
+
+-- Challenge 3 - Best Selling Authors
+
+SELECT * FROM sales;
+
+SELECT titleauthor.au_id AS author_id, authors.au_lname AS last_name , authors.au_fname AS first_name, SUM(qty) AS total
+FROM sales
+LEFT JOIN titleauthor ON sales.title_id = titleauthor.title_id 
+LEFT JOIN authors ON titleauthor.au_id = authors.au_id
+GROUP BY 1,2,3
+ORDER BY 4 DESC
+LIMIT 3;
+
+-- Challenge 4 - Best Selling Authors Ranking
+
+SELECT titleauthor.au_id AS author_id, 
+    authors.au_lname AS last_name, 
+    authors.au_fname AS first_name, 
+    SUM(CASE WHEN qty != 0 THEN qty ELSE 0 END) AS total
+FROM  authors
+LEFT JOIN  titleauthor ON titleauthor.au_id = authors.au_id
+LEFT JOIN  sales ON sales.title_id = titleauthor.title_id 
+GROUP BY titleauthor.au_id, authors.au_lname, authors.au_fname
+ORDER BY total DESC;