[lab-mysql-select] GonzaloBenitez

your-code/solution_select_mysql_lab.sql

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+/*Challenge 1: Who Have Published What At Where?*/
+use austin_weather;
+
+select * from authors;
+select * from titles;
+select * from publishers;
+select * from titleauthor Limit 5;
+select COUNT(au_id) from titleauthor;
+
+/* We need the ID, au_fname, au_lname from authors table 
+publisher_name from the publishers table 
+title from titles table*/
+
+
+DROP TABLE IF EXISTS aux_titles;
+CREATE TEMPORARY TABLE aux_titles
+SELECT titles.title_id, publishers.pub_name, titles.title
+FROM titles RIGHT JOIN publishers
+ON titles.pub_id = publishers.pub_id;
+
+DROP TABLE IF EXISTS aux_authors;
+CREATE TEMPORARY TABLE aux_authors
+SELECT titleauthor.au_id, aux_titles.pub_name, aux_titles.title, aux_titles.title_id
+FROM titleauthor RIGHT JOIN aux_titles
+ON titleauthor.title_id = aux_titles.title_id;
+
+SELECT * FROM aux_authors;
+
+DROP TABLE IF EXISTS aux_table;
+CREATE TEMPORARY TABLE aux_table
+SELECT authors.au_id AS "AUTHOR ID", authors.au_lname AS "LAST NAME", authors.au_fname AS "FIRST NAME",
+aux_authors.title AS "TITLE", aux_authors.pub_name AS "PUBLISHER", aux_authors.title_id
+FROM authors RIGHT JOIN aux_authors
+ON authors.au_id = aux_authors.au_id;
+
+SELECT * FROM aux_table;
+
+SELECT COUNT(authors.au_id) FROM aux_table;
+
+/*Challenge 2: Who Have Published How Many At Where? */
+
+SELECT `AUTHOR ID`, `LAST NAME`, `FIRST NAME`, `PUBLISHER`, COUNT(`TITLE`) AS "TITLE_COUNT"
+FROM aux_table
+GROUP BY `AUTHOR ID`, `LAST NAME`, `FIRST NAME`, `PUBLISHER`;
+
+SELECT SUM(TITLE_COUNT) AS TOTAL_TITLE_COUNT
+FROM (
+    SELECT `AUTHOR ID`, `LAST NAME`, `FIRST NAME`, `PUBLISHER`, COUNT(`TITLE`) AS "TITLE_COUNT"
+    FROM aux_table
+    GROUP BY `AUTHOR ID`, `LAST NAME`, `FIRST NAME`, `PUBLISHER`
+) AS subquery;
+
+SELECT COUNT(au_id) FROM titleauthor;
+
+/*Looks good*/
+
+/* Challenge 3 - Best Selling Authors */
+DROP TABLE IF EXISTS aux_sales;
+CREATE TEMPORARY TABLE aux_sales
+SELECT `AUTHOR ID`, `LAST NAME`, `FIRST NAME`,
+SUM(sales.qty) AS TOTAL
+FROM aux_table LEFT JOIN sales
+ON aux_table.title_id = sales.title_id
+GROUP BY
+	`AUTHOR ID`,
+    `LAST NAME`,
+    `FIRST NAME`;
+
+SELECT * FROM aux_sales ORDER BY TOTAL DESC LIMIT 3;