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[lab-intro-prob] Ana Santana #200

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lab done
anarsantana Aug 7, 2023
fa1678f
lab done
anarsantana Aug 7, 2023
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240 changes: 215 additions & 25 deletions your-code/main.ipynb
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Original file line number Diff line number Diff line change
Expand Up @@ -19,13 +19,70 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 1,
"metadata": {},
"outputs": [],
"source": [
"\"\"\"\n",
"your solution here\n",
"\"\"\""
"# P(A and B) = P(A) * P(B) # if A and B are independent\n",
"# P(A and B) = 0.01\n",
"\n",
"#P(A) * P(B)= 0.60*0.30\n",
"\n",
"## with this we can say that A and B are not independent!!! :D"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"1.\n",
"\n",
"- P(A U B)= P(A) + P(B) - P(A and B)\n",
"- P(A U B)= 0.30 + 0.60 -0.10\n",
"- P(A U B)= 0.80 </br>\n",
"The statement are **False**\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"2. \n",
"- P(A)- P(A∩B)\n",
"- 0.3 - 0.1 = 0.2 </br>\n",
"The statement are **true**\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"3. \n",
"- 𝑃(𝐴∩(𝐵∪𝐵𝐶))=0.4 \n",
"\n",
"- P(A∩B) + P(A) - P(A∩B)\n",
"- 0.1 + 0.3 -0.1 = 0.3 </br>\n",
"The statement are **False**\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"4.\n",
"- 𝑃(𝐴𝐶∩𝐵𝐶) = 1 - 𝑃(𝐴∪𝐵) \n",
"- = 1 - 0.8 = 0.2 </br>\n",
"The statement are **False**"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"5.\n",
"- 𝑃((𝐴∩𝐵)𝐶) = 1 - 𝑃(𝐴∩𝐵) \n",
"- = 1 - 0.1 = 0.9 </br>\n",
"The statement are **True**"
]
},
{
Expand All @@ -43,14 +100,23 @@
]
},
{
"cell_type": "code",
"execution_count": null,
"cell_type": "markdown",
"metadata": {},
"outputs": [],
"source": [
"\"\"\"\n",
"your solution here\n",
"\"\"\""
"w = 10 </br>\n",
"r = 12 </br>\n",
"b = 8 </br>\n",
"\n",
"1. P(w)= 10/30 = 0,33\n",
"2. P(w) = 10/29= 0,34\n",
"3. P(r)= 12/28= 0,42\n",
"\n",
"4. P = P(b) * P(r) * P(r2)\n",
"\n",
"P= (8/30) * (12/30) * (12/30)</br>\n",
"P = 0.042</br>\n",
"\n",
"**P(r2)= probability of taking the red ball again**\n"
]
},
{
Expand All @@ -68,15 +134,38 @@
"What is the probability of rain, given the day started cloudy?"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"ca= 0.50</br>\n",
"rb=0.40</br>\n",
"m=0.1</br>\n",
"\n",
"**P(A|B) = (P(B|A) * P (A))/P (B)**</br>\n",
"\n",
"P= (0,1 * 0,50) / 0,40</br>\n",
"P= 0.125 * 100 = 12,5"
]
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 12,
"metadata": {},
"outputs": [],
"outputs": [
{
"data": {
"text/plain": [
"12.5"
]
},
"execution_count": 12,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"\"\"\"\n",
"your solution here\n",
"\"\"\""
"((0.1*0.50)/0.40)*100"
]
},
{
Expand All @@ -102,28 +191,129 @@
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 3,
"metadata": {},
"outputs": [],
"outputs": [
{
"data": {
"text/html": [
"<div>\n",
"<style scoped>\n",
" .dataframe tbody tr th:only-of-type {\n",
" vertical-align: middle;\n",
" }\n",
"\n",
" .dataframe tbody tr th {\n",
" vertical-align: top;\n",
" }\n",
"\n",
" .dataframe thead th {\n",
" text-align: right;\n",
" }\n",
"</style>\n",
"<table border=\"1\" class=\"dataframe\">\n",
" <thead>\n",
" <tr style=\"text-align: right;\">\n",
" <th></th>\n",
" <th>Gender</th>\n",
" <th>Yes</th>\n",
" <th>No</th>\n",
" <th>total</th>\n",
" </tr>\n",
" </thead>\n",
" <tbody>\n",
" <tr>\n",
" <th>0</th>\n",
" <td>male</td>\n",
" <td>324</td>\n",
" <td>156</td>\n",
" <td>480</td>\n",
" </tr>\n",
" <tr>\n",
" <th>1</th>\n",
" <td>female</td>\n",
" <td>351</td>\n",
" <td>169</td>\n",
" <td>520</td>\n",
" </tr>\n",
" </tbody>\n",
"</table>\n",
"</div>"
],
"text/plain": [
" Gender Yes No total\n",
"0 male 324 156 480\n",
"1 female 351 169 520"
]
},
"execution_count": 3,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"# your code here"
"import pandas as pd\n",
"\n",
"data = {'Gender': ['male', 'female'],\n",
" 'Yes': ['324', '351'],\n",
" 'No': ['156', '169'],\n",
" 'total': ['480','520']}\n",
"\n",
"df = pd.DataFrame(data)\n",
"\n",
"df"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"The answer is yes, so the person that answered thinks that more street lighting is needed.</br>\n",
"The person who answered is a man.</br>\n",
"\n",
"male= 480</br>\n",
"male_yes= 324</br>\n",
"male_no= 156</br>\n",
"\n",
"female= 520</br>\n",
"female_yes= 351</br>\n",
"female_no= 169</br>\n",
"\n",
"\n",
"P(A|B) = male_yes / male </br>\n",
"P(A|B) = 324 / 480 = 0.675</br>\n",
"\n",
"\n",
"P(A) = (male_yes + female_yes) / (male + female) </br>\n",
"P(A) = (324 + 351) / (480 + 520) = 0.675</br>\n",
"\n",
"**RESULT** - P(A|B) = P(A) the events are independent. </br>\n",
"Based on the data, there is no strong indication that the desire for more street lighting depends on whether one is male or female."
]
},
{
"cell_type": "code",
"execution_count": null,
"execution_count": 5,
"metadata": {},
"outputs": [],
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"0.675\n",
"0.675\n"
]
}
],
"source": [
"\"\"\"\n",
"your solution here\n",
"\"\"\""
"print(324/480)\n",
"print((324+351)/(480+520))"
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Python 3",
"display_name": "Python 3 (ipykernel)",
"language": "python",
"name": "python3"
},
Expand All @@ -137,7 +327,7 @@
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.7.2"
"version": "3.10.9"
}
},
"nbformat": 4,
Expand Down