use proper exception for timeout

setup.py

@@ -3,7 +3,7 @@
 setup(
     name='pyzmqrpc',
     packages=['zmqrpc'],
-    version='2.0.0',
+    version='2.0.1',
     include_package_data=True,
     description='A simple ZMQ RPC extension with JSON for message serialization',
     author='J Verhoeven',

zmqrpc/ZmqExceptions.py

@@ -0,0 +1,11 @@
+'''
+Created on Dec 10, 2017
+
+@author: Pieter Eendebak
+
+@copyright: MIT license, see http://opensource.org/licenses/MIT
+'''
+
+
+class ZmqTimeoutException(Exception):
+    pass

zmqrpc/ZmqSender.py

@@ -10,6 +10,7 @@
 import time
 
 import zmq
+from .ZmqExceptions import ZmqTimeoutException
 
 logger = logging.getLogger("zmqrpc")
 
@@ -178,7 +179,7 @@ def _send_over_req_socket(self, message, time_out_waiting_for_response_in_sec=10
                             return self.handle_response(response_message_json)
                 # Some unexpected socket related error occurred. Recreate the REQ socket.
                 self.recreate_req_socket = True
-                raise Exception("No response received on ZMQ Request to end point {0} in {1} seconds. Discarding message. Marking REQ socket to be recreated on next try.".format(self.zmq_req_endpoints, time_out_waiting_for_response_in_sec))
+                raise ZmqTimeoutException("No response received on ZMQ Request to end point {0} in {1} seconds. Discarding message. Marking REQ socket to be recreated on next try.".format(self.zmq_req_endpoints, time_out_waiting_for_response_in_sec))
 
     def send(self, message, time_out_waiting_for_response_in_sec=60):
         # Create sockets if needed. Raise an exception if any problems are encountered