LeetCode40 Done #73
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LeetCode40 Done #73
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Test1/src/leetcode/LeetCode40.java
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| int[] candidatesSort = new int[candidatesSize + 1]; | ||
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| for(int num : candidates) { | ||
| candidatesSort[num]++; |
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I'm personally against counting sort in almost any cases.
If you use counting sort, the space complexity will be dependent upon the maximum number, and this is not ideal.
I think a standard O(NlogN) sorting method would be enough in this case.
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Time Complexity : O(NM)