fix: correctly remove indentation one line even if escaped line brake #144
Conversation
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
Close #141. ``` [fmtTrim| foo\ bar |] ``` should be `foobar` instead of `foo bar`. This is fixed by doing the whitespace trimming on the input string of the quasiquotes (here `\n foo\ bar`) instead of the output string. However it breaks two previous features: - When an interpolation block had whitespace, it should now be indented at least as much as the string, otherwise the interpolation block indentation will be used as reference. - Escaping the first line is now ignored. But actually, escaping the first line behaves exactly as not escaping the first line, so it breaks nothing.
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
Add this suggestion to a batch that can be applied as a single commit.
This suggestion is invalid because no changes were made to the code.
Suggestions cannot be applied while the pull request is closed.
Suggestions cannot be applied while viewing a subset of changes.
Only one suggestion per line can be applied in a batch.
Add this suggestion to a batch that can be applied as a single commit.
Applying suggestions on deleted lines is not supported.
You must change the existing code in this line in order to create a valid suggestion.
Outdated suggestions cannot be applied.
This suggestion has been applied or marked resolved.
Suggestions cannot be applied from pending reviews.
Suggestions cannot be applied on multi-line comments.
Suggestions cannot be applied while the pull request is queued to merge.
Suggestion cannot be applied right now. Please check back later.
Close #141.
should be
foobarinstead offoo bar.This is fixed by doing the whitespace trimming on the input string of
the quasiquotes (here
\n foo\ bar) instead of the output string.However it breaks two previous features: