Week9_Lab_joins

lab-sql-joins.sql

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+USE sakila;
+
+-- 1. List the number of films per category.
+SELECT c.name, COUNT(fc.film_id) AS film_count 
+FROM category AS c
+JOIN film_category AS fc ON c.category_id = fc.category_id
+JOIN film AS f ON fc.film_id = f.film_id
+GROUP BY c.name
+ORDER BY film_count DESC;
+
+-- 2. Retrieve the store ID, city, and country for each store.
+SELECT s.store_id, ct.city, c.country
+FROM store AS s
+LEFT JOIN address AS a ON s.address_id = a.address_id
+LEFT JOIN city AS ct ON a.city_id = ct.city_id
+LEFT JOIN country AS c ON ct.country_id = c.country_id;
+
+-- 3. Calculate the total revenue generated by each store in dollars.
+SELECT s.store_id, SUM(p.amount) AS total_revenue
+FROM store AS s
+JOIN staff AS st ON s.store_id = st.store_id
+JOIN payment AS p ON st.staff_id = p.staff_id
+GROUP BY s.store_id
+ORDER BY total_revenue DESC;
+
+-- 4. Determine the average running time of films for each category.
+SELECT c.name AS category, ROUND(AVG(f.length), 2) AS avg_duration
+FROM category AS c
+JOIN film_category AS fc ON c.category_id = fc.category_id
+JOIN film AS f ON fc.film_id = f.film_id
+GROUP BY c.name
+ORDER BY avg_duration DESC;
+
+-- Bonus:
+-- 5. Identify the film categories with the longest average running time.
+SELECT c.name AS category, ROUND(AVG(f.length), 2) AS avg_duration
+FROM category AS c
+JOIN film_category AS fc ON c.category_id = fc.category_id
+JOIN film AS f ON fc.film_id = f.film_id
+GROUP BY c.name
+ORDER BY avg_duration DESC
+LIMIT 5;
+
+-- 6. Display the top 10 most frequently rented movies in descending order.
+SELECT f.title AS film, COUNT(r.rental_id) AS rental_count
+FROM film AS f
+JOIN inventory as i ON f.film_id = i.film_id
+JOIN rental AS r ON i.inventory_id = r.inventory_id
+GROUP BY f.film_id, f.title 
+ORDER BY rental_count DESC
+LIMIT 10;
+
+-- 7. Determine if "Academy Dinosaur" can be rented from Store 1.
+SELECT f.title AS film, i.store_id
+FROM film AS f
+JOIN inventory AS i ON f.film_id = i.film_id
+WHERE f.title = 'Academy Dinosaur' AND i.store_id = 1;
+-- Or:
+SELECT
+  CASE 
+    WHEN COUNT(*) > 0 THEN f.title
+    ELSE 'No'
+  END AS available_in_store_1
+FROM film f
+JOIN inventory i ON f.film_id = i.film_id
+WHERE f.title = 'Academy Dinosaur'
+  AND i.store_id = 1;
+
+-- 8. Provide a list of all distinct film titles, along with their availability status in the inventory. 
+-- Include a column indicating whether each title is 'Available' or 'NOT available.
+-- ' Note that there are 42 titles that are not in the inventory, and this information can be obtained using a CASE statement combined with IFNULL."
+SELECT 
+    f.title,
+    CASE 
+        WHEN IFNULL(i.inventory_id, 0) = 0 THEN 'NOT available'
+        ELSE 'Available'
+    END AS availability_status
+FROM film f
+LEFT JOIN inventory i 
+    ON f.film_id = i.film_id;