lab solved

sakila3.sql

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+-- Write SQL queries to perform the following tasks using the Sakila database:
+USE Sakila;
+
+-- 1. List the number of films per category.
+-- checking what the table looks like
+
+SELECT COUNT(fc.film_id) AS number_of_films, c.name AS cat_name
+FROM sakila.film_category as fc
+join sakila.category as c
+ON fc.category_id = c.category_id
+GROUP BY cat_name;
+
+-- 2. Retrieve the store ID, city, and country for each store.
+-- checking table content
+SELECT * FROM sakila.address;
+
+SELECT s.store_id, ci.city, co.country 
+FROM sakila.store AS s
+JOIN sakila.address a
+ON s.address_id = a.address_id
+JOIN sakila.city ci
+ON a.city_id = ci.city_id
+JOIN sakila.country co
+ON ci.country_id = co.country_id
+ORDER BY co.country;
+
+-- 3. Calculate the total revenue generated by each store in dollars.
+-- check table
+SELECT * FROM sakila.payment;
+
+SELECT s.store_id, SUM(p.amount)
+FROM sakila.store AS s
+JOIN sakila.staff st
+ON s.store_id = st.store_id
+JOIN sakila.payment p 
+ON st.staff_id = p.staff_id
+GROUP BY s.store_id;
+
+-- 4. Determine the average running time of films for each category.
+SELECT c.name AS cat_name, ROUND(AVG(f.length),2) as avg_length
+FROM sakila.film AS f
+Join sakila.film_category fc
+ON f.film_id = fc.film_id
+join sakila.category c
+ON fc.category_id = c.category_id
+GROUP BY cat_name;
+-- Bonus:
+-- 5. Identify the film categories with the longest average running time.
+SELECT c.name AS cat_name, ROUND(AVG(f.length),2) as avg_length
+FROM sakila.film AS f
+Join sakila.film_category fc
+ON f.film_id = fc.film_id
+join sakila.category c
+ON fc.category_id = c.category_id
+GROUP BY cat_name
+ORDER BY avg_length DESC
+LIMIT 3;
+-- 6. Display the top 10 most frequently rented movies in descending order.
+SELECT * FROM sakila.rental;
+
+SELECT f.title AS film, COUNT(r.inventory_id) AS times_rented
+FROM sakila.rental AS r
+JOIN sakila.inventory AS i
+ON r.inventory_id = i.inventory_id
+JOIN sakila.film AS f
+ON i.film_id = f.film_id
+GROUP BY f.film_id
+ORDER BY times_rented DESC
+LIMIT 10;
+
+-- 7. Determine if "Academy Dinosaur" can be rented from Store 1.
+
+SELECT f.title, i.store_id
+FROM sakila.film AS f
+JOIN sakila.inventory as i
+ON f.film_id = i.film_id
+WHERE f.title = 'Academy Dinosaur';
+-- 8. Provide a list of all distinct film titles, along with their availability status in the inventory. 
+-- Include a column indicating whether each title is 'Available' or 'NOT available.' 
+-- Note that there are 42 titles that are not in the inventory, and this information can be obtained using a CASE statement combined with IFNULL."
+select * from sakila.inventory;
+
+
+SELECT DISTINCT(f.title),
+CASE
+	WHEN COUNT(i.inventory_id) = 0 THEN 'Not Available'
+    ELSE 'available'
+END AS RENTAL_STATUS
+FROM sakila.film AS f
+LEFT JOIN sakila.inventory AS i
+ON f.film_id = i.film_id
+LEFT JOIN sakila.rental AS r 
+ON i.inventory_id = r.inventory_id
+AND r.return_date is NULL
+GROUP BY f.title
+ORDER BY RENTAL_STATUS, f.title;