SESION3

SESIONES/Session_3/inner join.sql

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+----- sesion 3
+
+
+SELECT 
+    f.title AS "Film Title", 
+    COUNT(fa.actor_id) AS "Actor Count"
+FROM 
+    film f
+INNER JOIN 
+    film_actor fa ON f.film_id = fa.film_id
+GROUP BY f.title
+order by f.title
+
+
+
+-- CUALES SON LAS PELIS CON MAS DE 2 ACTORES
+SELECT 
+    f.title AS "Film Title", 
+    COUNT(fa.actor_id) AS "Actor Count"
+FROM 
+    film f
+INNER JOIN 
+    film_actor fa ON f.film_id = fa.film_id
+GROUP BY 
+    f.title
+HAVING 
+    COUNT(fa.actor_id) > 2
+ORDER BY 
+    COUNT(fa.actor_id) DESC;
+
+-- PELICULA CON MAS ACTORES, LIMITAR A UNO DESCENDIENTE
+SELECT 
+    f.title AS "Film Title", 
+    COUNT(fa.actor_id) AS "Actor Count"
+FROM 
+    film f
+INNER JOIN 
+    film_actor fa ON f.film_id = fa.film_id
+GROUP BY 
+    f.title
+ORDER BY 
+    COUNT(fa.actor_id) DESC
+LIMIT 1;
+
+--- Lista de Actores que salen en cada pelicula
+Select a.title, ARRAY_AGG (b.first_name|| ' ' || b.last_name) actors 
+from film a
+left join film_actor c
+	on a.film_id = c.film_id
+left join actor b
+	on c.actor_id = b.actor_id	
+Group by a.film_id
+
+-- ALTER TABLE
+ALTER TABLE staff
+DROP COLUMN family_problems;
+
+select *
+from staff
+
+--- CREAR VISTA
+CREATE VIEW mauro_balaguer AS
+SELECT 
+    a.first_name || ' ' || a.last_name AS "Actores",
+    f.title AS "Peliculas"
+FROM 
+    actor a
+JOIN 
+    film_actor fa ON a.actor_id = fa.actor_id -- Relaciona actores con películas
+JOIN 
+    film f ON fa.film_id = f.film_id -- Relaciona la película con la tabla 'film'
+ORDER BY 
+    f.title DESC;
+
+SELECT * FROM mauro_balaguer;
+
+SELECT * 
+FROM mauro_balaguer
+WHERE "Actores" = 'Lisa Monroe'
+ORDER BY "Peliculas" DESC;
+
+-- Muestra solo los 3 mejores clientes
+CREATE VIEW best_customers AS
+SELECT 
+    c.customer_id,
+    c.first_name || ' ' || c.last_name AS "Customer Name",
+    SUM(p.amount) AS "Total Spent"  -- Asumiendo que 'amount' es el monto de pago
+FROM 
+    customer c
+JOIN 
+    payment p ON p.customer_id = c.customer_id  -- Relaciona clientes con sus pagos
+GROUP BY 
+    c.customer_id, c.first_name, c.last_name  -- Agrupa por cliente
+ORDER BY 
+    "Total Spent" DESC  -- Ordena por el total gastado, de mayor a menor
+LIMIT 3;  
+
+SELECT *
+FROM best_customers
+
+-- Muestra solo los 3 peores clientes
+CREATE VIEW worst_customers AS
+SELECT 
+    c.customer_id, c.first_name || ' ' || c.last_name AS "Customer Name",
+    SUM(p.amount) AS "Total Spent"  -- Asumiendo que 'amount' es el monto de pago
+FROM 
+    customer c
+JOIN 
+    payment p ON p.customer_id = c.customer_id  -- Relaciona clientes con sus pagos
+GROUP BY 
+    c.customer_id, c.first_name, c.last_name  -- Agrupa por cliente
+ORDER BY 
+    "Total Spent" ASC  -- Ordena por el total gastado, de mayor a menor
+LIMIT 3;  
+
+select *
+from worst_customers
+
+select * from best_customers
+union
+select * from worst_customers
+order by "Total Spent" DESC
+
+-- sacar todas las peliculas en ingles, con subconsulta WHERE
+SELECT f.title
+from film f
+
+WHERE language_id IN 
+(SELECT language_id
+	  from language l
+	  where l.name = 'English')
+
+SELECT f.title,l.name -- select count(*)
+from film f
+JOIN language l on f.language_id = l.language_id
+WHERE l.name = 'English'
+
+select *
+from language
+
+WITH clientes_mas_190_gasto AS
+(
+SELECT
+	c.first_name || ' ' || c.last_name AS "Client Name", 
+	SUM(p.amount) AS Total_Spent
+FROM 
+	customer c
+JOIN 
+	payment p ON c.customer_id = p.customer_id
+GROUP BY 
+	c.first_name, c.last_name, c.customer_id
+ORDER BY 
+	Total_Spent DESC
+) 
+SELECT * FROM clientes_mas_190_gasto
+WHERE Total_Spent > 190