Solution submission

python/solution.py

@@ -0,0 +1,54 @@
+from textwrap import *
+
+message = "IKEWENENXLNQLPZSLERUMRHEERYBOFNEINCHCV"
+key = "SUPERSPY"
+
+##def print_grid(grid):
+##    for i in range(25):
+##        if i % 5 == 0:
+##            print("")
+##        print(grid[i], end="")
+##    print("")
+
+def create_grid(key, omit=""): 
+    result = "".join(dict.fromkeys(omit + key)) # removes duplicates by generating a dictionary
+    count = 0                                   # then join all of the keys together to form a new string
+                                                # omit is added first to be removed later
+    while len(result) < 25 + len(omit):
+        result = "".join(dict.fromkeys(result + chr(ord("A") + count))) # increment alphabetically, and it skips existing letters for meeeee
+        count += 1
+
+    return result[len(omit):]       # let's get rid of the stuff we wanted to omit
+
+new_grid = create_grid(key, "J")    # generate my grid!
+split_message = wrap(message, 2)    # split my encrypted message into pairs
+solution = ""                       # for the final solution
+
+while(len(split_message) > 0):
+    pair = split_message.pop(0)
+
+    if new_grid.index(pair[0]) // 5 == new_grid.index(pair[1]) // 5: # case 1, they're in the same row
+        offset = new_grid.index(pair[0]) // 5 * 5   # gives me my row offset value
+
+        solution += ( # string append
+            new_grid[offset + (new_grid.index(pair[0]) - 1) % 5] +  # move 1 to the left, modulus helps me wrap around
+            new_grid[offset + (new_grid.index(pair[1]) - 1) % 5]    # second character
+            )
+
+    elif new_grid.index(pair[0]) % 5 == new_grid.index(pair[1]) % 5: # case two, they're in the same column
+        offset = new_grid.index(pair[0]) % 5 # gives me my column offset value
+
+        solution += (
+            new_grid[offset + (new_grid.index(pair[0] // 5 - 1)) % 5 * 5] + # move 1 upwards, so 5 index positions, modulus wrap
+            new_grid[offset + (new_grid.index(pair[1] // 5 - 1)) % 5 * 5]   # and then column offset gets added last, thanks BEDMAS
+            )
+
+    else: # case 3, box!
+        x0 = new_grid.index(pair[0]) % 5 
+        y0 = new_grid.index(pair[0]) // 5 * 5
+        x1 = new_grid.index(pair[1]) % 5 
+        y1 = new_grid.index(pair[1]) // 5 * 5
+
+        solution += (new_grid[y0 + x1] + new_grid[y1 + x0]) # swapping columns of the characters, making the box!
+
+[print(i, end="") for i in solution if i != "X" and i.isalpha()] # prints, omitting X and making sure it's in the alphabet