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Lab1 SQL Select.sql

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+-- SQL Select Lab
+-- Question 1.
+use sakila;
+select * from actor;
+	select count(distinct(last_name)) from actor;
+	-- 121
+
+-- 2. 
+select * from film;
+	select count(distinct(language_id)) from film;
+	-- 1 
+
+-- 3.
+select count(rating) from film
+    where rating = "PG-13";
+	-- 223
+
+-- 4.
+select title from film
+	where release_year = '2006'
+	order by length desc
+    limit 10;
+
+	-- 'DARN FORRESTER'
+	-- 'POND SEATTLE'
+	-- 'CHICAGO NORTH'
+	-- 'MUSCLE BRIGHT'
+	-- 'WORST BANGER'
+	-- 'GANGS PRIDE'
+	-- 'SOLDIERS EVOLUTION'
+	-- 'HOME PITY'
+	-- 'SWEET BROTHERHOOD'
+	-- 'CONTROL ANTHEM'
+
+-- 5.
+select rental_date from rental;
+	select datediff(max(rental_date), min(rental_date)) as date_difference
+    from rental;
+    -- 266 days
+
+-- 6.
+select rental_date, dayname(rental_date) as day_of_week, monthname(rental_date) as month from rental
+limit 20;
+
+-- 7.
+select*,
+    case 
+		when dayofweek(rental_date) in (1, 7) then "Weekend"
+		else "Workday"
+		end as day_type
+    from rental;
+
+-- 8.
+select max(rental_date)
+from rental;
+-- max rental date is 2006-02-14
+select count(rental_date) from rental
+	where rental_date between "2006-01-14" and "2006-02-15";
+-- 182 rentals in last month of activity
+
+-- 9.
+select title, rating from film;
+
+-- 10.
+select title, release_year from film;
+
+-- 11.
+select title from film
+	where title like "%ARMAGEDDON%";
+
+-- 12. 
+select title from film
+	where title like "%APOLLO%";
+
+-- 13. 
+select title from film
+	where title like "%APOLLO";
+
+-- 14.
+select title from film
+	where title like "%DATE%";
+
+-- 15.
+select title from film
+	order by length(title) desc
+    limit 10;
+
+-- 16.
+select title, length from film
+	order by length desc
+    limit 10;
+
+-- 17.
+select count(*) from film
+	where special_features like "%Behind the Scenes%";
+	-- 538
+
+-- 18.
+select title, release_year from film
+	order by release_year and title;
+
+-- 19.
+alter table staff
+drop column picture;
+
+-- 20.
+SELECT * FROM customer
+WHERE first_name = "Tammy" AND last_name="Sanders";
+INSERT INTO staff (staff_id, first_name, last_name, address_id, email, store_id, active, username, password, last_update)
+VALUES (3, "tammy", "sanders", 79, "TAMMY.SANDERS@sakilacustomer.org", 2, 1,  "Tammy", null, "2006-02-15 04:57:20");
+
+-- 21.
+
+select customer_id from sakila.customer
+where first_name = 'CHARLOTTE' and last_name = 'HUNTER';
+-- customer ID = 130
+
+select staff_id from sakila.staff
+where first_name = 'Mike' and last_name = 'Hillyer';
+
+select inventory_id from rental
+where customer_id = 130 and staff_id = 1 and store_id = 1;
+
+select film_id from film
+where title = "Academy Dinosaur";
+
+select inventory_id from inventory
+where film_id = 1 and store_id = 1;
+
+select last_update from film
+where film_id = 1 and title = "Academy Dinosaur";
+
+select inventory_id from inventory
+where last_update = "2006-02-15 05:03:42" and film_id = 1 and store_id = 1;
+
+insert into rental (rental_date, inventory_id, customer_id, staff_id, last_update)
+values ("2023-10-25 18:57:17", 4, 130, 1, now());
+
+select * from rental
+where customer_id = 130 and inventory_id = 4;
+
+    insert into rental(day_type)
+    values(case 
+		when dayofweek(rental_date) in (1, 7) then "Weekend"
+		else "Workday"
+        end)
+    where rental_id = 16050;
+    -- esto no funciona
+
+    SET SQL_SAFE_UPDATES=0;
+UPDATE Rental
+SET day_type = CASE 
+    WHEN DAYOFWEEK(rental_date) IN (1, 7) THEN 'weekend'
+    ELSE 'workday'
+END;
+SET SQL_SAFE_UPDATES=1;
+
+select * from rental
+where customer_id = 130 and inventory_id = 4;
+
+-- 22. 
+
+CREATE TABLE DELETED_USERS (
+    customer_id INT,
+    email VARCHAR(250),
+    deleted_date date
+    );
+INSERT INTO deleted_users (customer_id, email, deleted_date)
+SELECT customer_id, email, current_date
+FROM customer
+WHERE active = "0";
+select *
+from deleted_users;
+delete from customer
+where active = 0;
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