Completed week 2 homework

homeworks/kd_week2_hw.ipynb

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+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## ❌ DO NOT EDIT - MAKE A COPY\n",
+    "# Q1: Alphabet Slices\n",
+    "* Store the first ten letters of the alphabet in a list.\n",
+    "* Use a slice to print out the first three letters of the alphabet.\n",
+    "* Use a slice to print out any three letters from the middle of your list."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# Solve Alphabet slices here. \n",
+    "## Extra Credit:  Do this without 'hard coding' the alpahbet.\n",
+    "\n",
+    "\n"
+    #import string (not sure how to import here since i used on vs code)
+
+    alphabet = string.ascii_lowercase  
+
+    print(alphabet[:10]) 
+    print(alphabet[:3])   
+    print(alphabet[4:7])  
+
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Q2:  Covert all the rapper names to title case and save them into a new different list. \n",
+    "Example: **lil wayne** becomes **Lil Wayne**"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# Solve rapper names here\n",
+    "rappers = ['lil wayne', 'nicki minaj', 'drake']\n"
+     real_rappers = [name.title() for name in rappers]
+    print(real_rappers)
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Q3: Write a function that takes a number and returns:\n",
+    "* True if the input number is even.\n",
+    "* False if the input number is odd."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# Solve problem here\n",
+    "\n",
+    "def even_odd(lst):\n",
+    "   pass # replace this with your code\n",
+    "   # return something"
+    return lst % 2 == 0
+    #testing
+    print(even_odd(4))  # True
+    print(even_odd(7))  # False
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Q4: Find the sum and the average of this list of numbers.\n",
+    "\n",
+    "Try doing this using a loop.  Then try doing this without using a loop. "
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# Solve problem here:\n",
+    "\n",
+    "my_list = [1, 5, 10, 55, 88, 44, 42, 50, 20, 38]\n",
+    "list_sum = ???\n",
+    "list_avg = ???\n",
+    "\n",
+    "\n",
+    "# Keep this as your last line in this cell.\n",
+    "print(list_sum, list_average)"
+
+    total = 0
+    for num in my_list:
+    total += num
+    avg = total / len(my_list)
+
+    print(total, avg)
+
+# Without loop
+    total2 = sum(my_list)
+    avg2 = total2 / len(my_list)
+
+    print(total2, avg2)
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Q5: \n",
+    "## Write a function that takes a list and returns a new list that has all the duplicates removed.\n",
+    "\n",
+    "Example input and expected output:\n",
+    "- input = `[\"Michele\", \"Robin\", \"Sara\", \"Michele\"]`\n",
+    "- expected output = `['Michele', 'Robin', 'Sara']`\n"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# Solve problem here:\n",
+    "\n",
+    "names = [\"Michele\", \"Robin\", \"Sara\", \"Michele\"]\n"
+     unique_names = list(set(names))
+    print(unique_names)
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Q6: Write a function that takes a list of numbers \n",
+    "(for example, `a = [5, 10, 15, 20, 25]`) and returns a new list of only the first and last elements of the given list.\n",
+    "\n",
+    "Example input and expected output:\n",
+    "- input = `[5, 10, 15, 20, 25]`\n",
+    "- expected output = `[5, 25]`"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# Solve problem here:\n",
+    "input_list = [5, 10, 99, 20, 25]"
+    result = [input_list[0], input_list[-1]]
+    print(result)
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Q7: \n",
+    "## Implement a function that takes as input three variables, and returns the largest of the three. \n",
+    "### Try doing this without using the `max()` function!\n",
+    "\n",
+    "_**Note:** all three input numbers will always be different, no need to account for a tie._\n",
+    "\n",
+    "Example input and expected output:\n",
+    "- input: `your_function(1, 5, 10)`\n",
+    "- expected output:  `10`"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# Solve Problem here:\n",
+    "\n",
+    "def my_max(a, b, c):\n",
+    "    # Fill in your code below and return max value of a, b, c\n",
+    "    "
+   ]
+   def my_max(a, b, c):
+    if a > b and a > c:
+        return a
+    elif b > a and b > c:
+        return b
+    else:
+        return c
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# Test to see if your function works properly.\n",
+    "my_max(1, 5, 10)"
+    print(my_max(1, 5, 10))
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Q8: Write a function that takes a number as input and returns the following:\n",
+    "* If the input is divisible by three, return `'fizz'`\n",
+    "* If the input is divisible by five, return `'buzz'`\n",
+    "* If the input is divisible by three and by five, return `'fizzbuzz'`\n",
+    "* If the input is not divisible by three or five, return `None`."
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": null,
+   "metadata": {},
+   "outputs": [],
+   "source": [
+    "# Solve Problem fizzbuzz here:\n"
+    def fizzbuzz(n):
+    if n % 3 == 0 and n % 5 == 0:
+        return 'fizzbuzz'
+    elif n % 3 == 0:
+        return 'fizz'
+    elif n % 5 == 0:
+        return 'buzz'
+    else:
+        return None
+   ]
+  }
+ ],
+ "metadata": {
+  "kernelspec": {
+   "display_name": "Python 3 (ipykernel)",
+   "language": "python",
+   "name": "python3"
+  },
+  "language_info": {
+   "codemirror_mode": {
+    "name": "ipython",
+    "version": 3
+   },
+   "file_extension": ".py",
+   "mimetype": "text/x-python",
+   "name": "python",
+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython3",
+   "version": "3.12.4"
+  }
+ },
+ "nbformat": 4,
+ "nbformat_minor": 4
+}