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kyra-patton
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Jul 28, 2022
kyra-patton
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kyra-patton
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✨🌸 Nice work, Nourhan. I left a few minor suggestions. Let me know what questions you have.
🟢
| # Space Complexity: ? | ||
| # Time Complexity: O(1) | ||
| # Space Complexity: O(1) | ||
| def get_first(self): |
| # Time Complexity: O(1) | ||
| # Space Complexity: O(1) | ||
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| def add_first(self, value): |
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def search(self, value): |
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def length(self): |
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def get_at_index(self, index): |
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| if last_node.next is None: | ||
| break |
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🤓 We generally like to avoid break statements where possible. How might you refactor your code to eliminate this one?
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| # method to return the max value in the linked list | ||
| # returns the data value and not the node | ||
| def find_max(self): |
| def delete(self, value): | ||
| pass | ||
| # Head has the value to delete | ||
| if self.head is not None\ |
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Suggested change
| if self.head is not None\ | |
| if self.head is not None: | |
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) |
| current_node = next_node | ||
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| # method to print all the values in the linked list | ||
| # Time Complexity: ? |
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