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solutions.sql
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72 lines (56 loc) · 1.88 KB
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USE SAKILA;
-- 1
SELECT film.title , COUNT(inventory.inventory_id)
FROM film
JOIN inventory
ON film.film_id = inventory.film_id
WHERE film.title = "Hunchback Impossible";
-- 2
SELECT film.title,film.length
FROM film
WHERE film.length > (select avg(film.length) from film);
-- 3
SELECT CONCAT(actor.first_name, " ", actor.last_name) AS name
FROM actor
JOIN film_actor ON actor.actor_id = film_actor.actor_id
WHERE film_id
IN (SELECT film_id FROM film WHERE title = 'Alone Trip');
-- 4
SELECT title
FROM film
JOIN film_category ON film.film_id = film_category.film_id
WHERE category_id
IN (SELECT category_id FROM category WHERE category.name = 'family');
-- 5
SELECT CONCAT(customer.first_name, " ", customer.last_name) AS name, customer.email
FROM customer
JOIN address ON customer.address_id = address.address_id
JOIN city ON address.city_id = city.city_id
WHERE country_id
IN (SELECT country_id FROM country WHERE country.country = 'CANADA');
-- 6
SELECT CONCAT(actor.first_name, " ", actor.last_name) AS name, COUNT(film_actor.actor_id) AS times_appear
FROM actor
JOIN film_actor ON actor.actor_id = film_actor.actor_id
GROUP by name
ORDER BY times_appear DESC;
-- 7
SELECT film.title
FROM film
WHERE film.film_id IN
(SELECT film_id FROM inventory
WHERE inventory_id IN
(SELECT inventory_id FROM rental
WHERE rental_id IN
(SELECT rental_id FROM payment
WHERE customer_id =
(SELECT customer_id from payment
GROUP BY customer_id
ORDER by SUM(amount) DESC
LIMIT 1))));
-- 8
SELECT customer_id, SUM(amount) AS total_amount
FROM payment
GROUP BY customer_id
HAVING total_amount > (select avg(amount) from payment)
ORDER BY total_amount DESC;