Skip to content
Discussion options

You must be logged in to vote

Sorry for being so late to the part @azshe . I've been busy and such. Sorry about that.

Is the armi reactor loaded already when sweeping with an input modifier?

Nope. This is just before the Reactor gets created.

I'm wondering if the ARMI reactor itself is loaded when the sweep is kicked off?

Chris is correct. No Reactor objects are created during input modifier execution. But, of course, the __call__ method is a blank slate where you can inject any code you want.

Replies: 1 comment 5 replies

Comment options

You must be logged in to vote
5 replies
@azshe
Comment options

@john-science
Comment options

Answer selected by john-science
@john-science
Comment options

@azshe
Comment options

@john-science
Comment options

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Category
Q&A
Labels
None yet
3 participants