diff --git a/your-code/solutions.sql b/your-code/solutions.sql
new file mode 100644
index 0000000..a262b63
--- /dev/null
+++ b/your-code/solutions.sql
@@ -0,0 +1,88 @@
+/* Challenge 1 - Who Have Published What At Where? */
+SELECT
+    a.au_id AS 'AUTHOR ID',
+    a.au_lname AS 'LAST NAME',
+    a.au_fname AS 'FIRST NAME',
+    t.title AS 'TITLE',
+    p.pub_name AS 'PUBLISHER'
+FROM
+    titleauthor ta
+JOIN
+    authors a ON ta.au_id = a.au_id  -- Corrected to use ta.au_id
+JOIN
+    titles t ON ta.title_id = t.title_id
+JOIN
+    publishers p ON t.pub_id = p.pub_id;  -- Joining on pub_id
+
+/*Compare nuymber of rows in titleauthor vs my output */
+SELECT COUNT(*) AS total_records FROM titleauthor;
+
+/*My oputput */
+SELECT COUNT(*) AS total_output_rows
+FROM
+    titleauthor ta
+JOIN
+    authors a ON ta.au_id = a.au_id
+JOIN
+    titles t ON ta.title_id = t.title_id
+JOIN
+    publishers p ON t.pub_id = p.pub_id;
+
+    
+/*Challenge 2 - Who Have Published How Many At Where? */
+SELECT
+    a.au_id AS 'AUTHOR ID',
+    a.au_lname AS 'LAST NAME',
+    a.au_fname AS 'FIRST NAME',
+    p.pub_name AS 'PUBLISHER',
+    COUNT(t.title) AS 'TOTAL TITLES'
+FROM
+    titleauthor ta
+JOIN
+    authors a ON ta.au_id = a.au_id
+JOIN
+    titles t ON ta.title_id = t.title_id
+JOIN
+    publishers p ON t.pub_id = p.pub_id
+GROUP BY
+    a.au_id, p.pub_name
+ORDER BY
+    a.au_lname, p.pub_name;
+
+SELECT SUM(total_titles) AS 'TOTAL TITLE COUNT'
+FROM (
+    SELECT COUNT(t.title) AS total_titles
+    FROM titleauthor ta
+    JOIN authors a ON ta.au_id = a.au_id
+    JOIN titles t ON ta.title_id = t.title_id
+    JOIN publishers p ON t.pub_id = p.pub_id
+    GROUP BY a.au_id, p.pub_name
+) AS title_counts;
+
+SELECT COUNT(*) AS total_records FROM titleauthor;
+
+/*Challenge 3 - Best Selling Authors */
+SELECT a.au_id 'AUTHOR ID', a.au_lname 'LAST NAME', a.au_fname 'FIRST NAME',
+SUM(s.qty) 'TOTAL'
+FROM authors a
+JOIN titleauthor ta USING (au_id)
+JOIN titles t USING (title_id)
+JOIN sales s USING (title_id)
+GROUP BY a.au_id
+ORDER BY SUM(s.qty) DESC
+LIMIT 3;
+
+/*Challenge 4 - Best Selling Authors Ranking */
+SELECT a.au_id 'AUTHOR ID', a.au_lname 'LAST NAME', a.au_fname 'FIRST NAME',
+IFNULL(SUM(s.qty),0) AS 'TOTAL'
+FROM authors a
+LEFT JOIN titleauthor ta USING (au_id)
+LEFT JOIN titles t USING (title_id)
+LEFT JOIN sales s USING (title_id)
+GROUP BY a.au_id
+ORDER BY TOTAL DESC;
+
+
+
+
+