From 9e1100efdfce52de78f534e2b2f822d2609448a3 Mon Sep 17 00:00:00 2001 From: juan1309-ctr Date: Mon, 24 Jan 2022 00:12:51 -0600 Subject: [PATCH] Este es el laboratorio --- .../.ipynb_checkpoints/main-checkpoint.ipynb | 413 ++++++++++++++++++ your-code/main.ipynb | 253 +++++++---- 2 files changed, 584 insertions(+), 82 deletions(-) create mode 100644 your-code/.ipynb_checkpoints/main-checkpoint.ipynb diff --git a/your-code/.ipynb_checkpoints/main-checkpoint.ipynb b/your-code/.ipynb_checkpoints/main-checkpoint.ipynb new file mode 100644 index 0000000..c576048 --- /dev/null +++ b/your-code/.ipynb_checkpoints/main-checkpoint.ipynb @@ -0,0 +1,413 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Before your start:\n", + "- Read the README.md file\n", + "- Comment as much as you can and use the resources in the README.md file\n", + "- Happy learning!" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Challenge 1 - Passing a Lambda Expression to a Function\n", + "\n", + "In the next excercise you will create a function that returns a lambda expression. Create a function called `modify_list`. The function takes two arguments, a list and a lambda expression. The function iterates through the list and applies the lambda expression to every element in the list." + ] + }, + { + "cell_type": "raw", + "metadata": {}, + "source": [ + "Follow the steps as stated below:\n", + " 1. Define a list of any 10 numbers\n", + " 2. Define a simple lambda expression for eg that updates a number by 2\n", + " 3. Define an empty list\n", + " 4. Define the function -> use the lambda function to append the empty list\n", + " 5. Call the function with list and lambda expression\n", + " 6. print the updated list " + ] + }, + { + "cell_type": "code", + "execution_count": 18, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "1\n", + "2\n", + "3\n", + "4\n", + "5\n", + "6\n", + "7\n", + "8\n", + "9\n", + "10\n", + "[2, 4, 6, 8, 10, 12, 14, 16, 18, 20]\n" + ] + } + ], + "source": [ + "l = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]\n", + "f = list(map(lambda x:x*2, l))#define the lambda expression\n", + "b = []\n", + "#def modify_list(lst, fudduLambda):\n", + "for i in range(10):\n", + " j = lambda x, i=i: x + i\n", + " b.append(j)\n", + "for e in b:\n", + " print(e(1))\n", + "#print(Call modify_list(l,f))\n", + "print(f)\n" + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": {}, + "outputs": [], + "source": [ + "lista=[i for i in range(10)]" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Now we will define a lambda expression that will transform the elements of the list. \n", + "\n", + "In the cell below, create a lambda expression that converts Celsius to Kelvin. Recall that 0°C + 273.15 = 273.15K" + ] + }, + { + "cell_type": "code", + "execution_count": 21, + "metadata": { + "scrolled": true + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "[285.15, 296.15, 311.15, 218.14999999999998, 297.15]\n" + ] + } + ], + "source": [ + "temps = [12, 23, 38, -55, 24]\n", + "\n", + "# Your code here:\n", + "temperatura = list(map(lambda x: x + 273.15, temps))\n", + "print(temperatura)\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Finally, convert the list of temperatures below from Celsius to Kelvin." + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### In this part, we will define a function that returns a lambda expression\n", + "\n", + "In the cell below, write a lambda expression that takes two numbers and returns 1 if one is divisible by the other and zero otherwise. Call the lambda expression `mod`." + ] + }, + { + "cell_type": "code", + "execution_count": 99, + "metadata": { + "scrolled": true + }, + "outputs": [ + { + "data": { + "text/plain": [ + "1" + ] + }, + "execution_count": 99, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "mod = lambda x, y: 1 if y % x == 0 else 0\n", + "\n", + "mod(2, 6)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Now create a function that returns mod. The function only takes one argument - the first number in the `mod` lambda function. \n", + "\n", + "Note: the lambda function above took two arguments, the lambda function in the return statement only takes one argument but also uses the argument passed to the function." + ] + }, + { + "cell_type": "code", + "execution_count": 100, + "metadata": {}, + "outputs": [], + "source": [ + "def divisor(a):\n", + " \"\"\"\n", + " input: a number\n", + " output: a function that returns 1 if the number is divisible by another number (to be passed later) and zero otherwise\n", + " \"\"\"\n", + " # Your code here:\n", + " return lambda y: mod(a, y)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Finally, pass the number 5 to `divisor`. Now the function will check whether a number is divisble by 5. Assign this function to `divisible5`" + ] + }, + { + "cell_type": "code", + "execution_count": 104, + "metadata": {}, + "outputs": [], + "source": [ + "divisible5 = divisor(5)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Test your function with the following test cases:" + ] + }, + { + "cell_type": "code", + "execution_count": 105, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "1" + ] + }, + "execution_count": 105, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "divisible5(10)" + ] + }, + { + "cell_type": "code", + "execution_count": 106, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "0" + ] + }, + "execution_count": 106, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "divisible5(9)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Challenge 2 - Using Lambda Expressions in List Comprehensions\n", + "\n", + "In the following challenge, we will combine two lists using a lambda expression in a list comprehension. \n", + "\n", + "To do this, we will need to introduce the `zip` function. The `zip` function returns an iterator of tuples.\n", + "\n", + "The way zip function works with list has been shown below:" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "[('Green', 'eggs'),\n", + " ('cheese', 'cheese'),\n", + " ('English', 'cucumber'),\n", + " ('tomato', 'tomato')]" + ] + }, + "execution_count": 1, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "list1 = ['Green', 'cheese', 'English', 'tomato']\n", + "list2 = ['eggs', 'cheese', 'cucumber', 'tomato']\n", + "zipped = zip(list1,list2)\n", + "list(zipped)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "In this exercise we will try to compare the elements on the same index in the two lists. \n", + "We want to zip the two lists and then use a lambda expression to compare if:\n", + "list1 element > list2 element " + ] + }, + { + "cell_type": "code", + "execution_count": 60, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "[True, True, True, True]\n" + ] + } + ], + "source": [ + "compare = list(map(lambda x: x[0] < x[1], zip(list1, list2)))\n", + "print(compare)\n" + ] + }, + { + "cell_type": "raw", + "metadata": {}, + "source": [ + "Complete the parts of the code marked as \"###\"" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Challenge 3 - Using Lambda Expressions as Arguments\n", + "\n", + "#### In this challenge, we will zip together two lists and sort by the resulting tuple.\n", + "\n", + "In the cell below, take the two lists provided, zip them together and sort by the first letter of the second element of each tuple. Do this using a lambda function." + ] + }, + { + "cell_type": "code", + "execution_count": 66, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "[('Political Science', 'Essay'), ('Computer Science', 'Homework'), ('Engineering', 'Lab'), ('Mathematics', 'Module')]\n" + ] + } + ], + "source": [ + "list1 = ['Engineering', 'Computer Science', 'Political Science', 'Mathematics']\n", + "list2 = ['Lab', 'Homework', 'Essay', 'Module']\n", + "\n", + "# Your code here:\n", + "zipped=zip(list1, list2)\n", + "lista3= (list(zipped))\n", + "\n", + "lista3= sorted(lista3, key = lambda x: x[1])\n", + "\n", + "print(lista3)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Bonus Challenge - Sort a Dictionary by Values\n", + "\n", + "Given the dictionary below, sort it by values rather than by keys. Use a lambda function to specify the values as a sorting key." + ] + }, + { + "cell_type": "code", + "execution_count": 69, + "metadata": {}, + "outputs": [], + "source": [ + "d = {'Honda': 1997, 'Toyota': 1995, 'Audi': 2001, 'BMW': 2005}\n", + "\n", + "# Your code here:" + ] + }, + { + "cell_type": "code", + "execution_count": 70, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "[('Toyota', 1995), ('Honda', 1997), ('Audi', 2001), ('BMW', 2005)]" + ] + }, + "execution_count": 70, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "d = sorted (d. items(), key = lambda x : x [1])\n", + "d" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 3 (ipykernel)", + "language": "python", + "name": "python3" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 3 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython3", + "version": "3.9.7" + } + }, + "nbformat": 4, + "nbformat_minor": 2 +} diff --git a/your-code/main.ipynb b/your-code/main.ipynb index 66a9984..0f1f8aa 100644 --- a/your-code/main.ipynb +++ b/your-code/main.ipynb @@ -34,18 +34,48 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 18, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "1\n", + "2\n", + "3\n", + "4\n", + "5\n", + "6\n", + "7\n", + "8\n", + "9\n", + "10\n", + "[2, 4, 6, 8, 10, 12, 14, 16, 18, 20]\n" + ] + } + ], "source": [ - "l = [######]\n", - "f = lambda x: #define the lambda expression\n", + "l = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]\n", + "f = list(map(lambda x:x*2, l))#define the lambda expression\n", "b = []\n", - "def modify_list(lst, fudduLambda):\n", - " for x in ####:\n", - " b.append(#####(x))\n", - "#Call modify_list(##,##)\n", - "#print b" + "#def modify_list(lst, fudduLambda):\n", + "for i in range(10):\n", + " j = lambda x, i=i: x + i\n", + " b.append(j)\n", + "for e in b:\n", + " print(e(1))\n", + "#print(Call modify_list(l,f))\n", + "print(f)\n" + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": {}, + "outputs": [], + "source": [ + "lista=[i for i in range(10)]" ] }, { @@ -59,12 +89,25 @@ }, { "cell_type": "code", - "execution_count": 3, - "metadata": {}, - "outputs": [], + "execution_count": 21, + "metadata": { + "scrolled": true + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "[285.15, 296.15, 311.15, 218.14999999999998, 297.15]\n" + ] + } + ], "source": [ + "temps = [12, 23, 38, -55, 24]\n", + "\n", "# Your code here:\n", - "\n" + "temperatura = list(map(lambda x: x + 273.15, temps))\n", + "print(temperatura)\n" ] }, { @@ -74,17 +117,6 @@ "Finally, convert the list of temperatures below from Celsius to Kelvin." ] }, - { - "cell_type": "code", - "execution_count": 4, - "metadata": {}, - "outputs": [], - "source": [ - "temps = [12, 23, 38, -55, 24]\n", - "\n", - "# Your code here:" - ] - }, { "cell_type": "markdown", "metadata": {}, @@ -96,11 +128,26 @@ }, { "cell_type": "code", - "execution_count": 5, - "metadata": {}, - "outputs": [], + "execution_count": 139, + "metadata": { + "scrolled": true + }, + "outputs": [ + { + "data": { + "text/plain": [ + "0" + ] + }, + "execution_count": 139, + "metadata": {}, + "output_type": "execute_result" + } + ], "source": [ - "# Your code here:\n" + "mod = lambda x, y: 1 if y % x == 0 else 0\n", + "\n", + "mod(2, 7)" ] }, { @@ -114,17 +161,17 @@ }, { "cell_type": "code", - "execution_count": 6, + "execution_count": 140, "metadata": {}, "outputs": [], "source": [ - "def divisor(b):\n", + "def divisor(a):\n", " \"\"\"\n", " input: a number\n", " output: a function that returns 1 if the number is divisible by another number (to be passed later) and zero otherwise\n", " \"\"\"\n", - " \n", - " # Your code here:" + " # Your code here:\n", + " return lambda y: mod(a, y)" ] }, { @@ -136,11 +183,23 @@ }, { "cell_type": "code", - "execution_count": 7, + "execution_count": 141, "metadata": {}, - "outputs": [], + "outputs": [ + { + "data": { + "text/plain": [ + ".(y)>" + ] + }, + "execution_count": 141, + "metadata": {}, + "output_type": "execute_result" + } + ], "source": [ - "# Your code here:\n" + "divisible5 = divisor(5)\n", + "divisible5" ] }, { @@ -152,20 +211,42 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 144, "metadata": {}, - "outputs": [], + "outputs": [ + { + "data": { + "text/plain": [ + "0" + ] + }, + "execution_count": 144, + "metadata": {}, + "output_type": "execute_result" + } + ], "source": [ - "divisible5(10)" + "divisible5(12)" ] }, { "cell_type": "code", - "execution_count": null, + "execution_count": 145, "metadata": {}, - "outputs": [], + "outputs": [ + { + "data": { + "text/plain": [ + "1" + ] + }, + "execution_count": 145, + "metadata": {}, + "output_type": "execute_result" + } + ], "source": [ - "divisible5(8)" + "divisible5(5)" ] }, { @@ -218,14 +299,20 @@ }, { "cell_type": "code", - "execution_count": 3, + "execution_count": 60, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "[True, True, True, True]\n" + ] + } + ], "source": [ - "list1 = [1,2,3,4]\n", - "list2 = [2,3,4,5]\n", - "## Zip the lists together \n", - "## Print the zipped list " + "compare = list(map(lambda x: x[0] < x[1], zip(list1, list2)))\n", + "print(compare)\n" ] }, { @@ -235,32 +322,6 @@ "Complete the parts of the code marked as \"###\"" ] }, - { - "cell_type": "code", - "execution_count": 4, - "metadata": {}, - "outputs": [ - { - "data": { - "text/plain": [ - "'\\n\\ncompare = lambda ###: print(\"True\") if ### else print(\"False\")\\nfor ### in zip(list1,list2):\\n compare(###)\\n \\n'" - ] - }, - "execution_count": 4, - "metadata": {}, - "output_type": "execute_result" - } - ], - "source": [ - "'''\n", - "\n", - "compare = lambda ###: print(\"True\") if ### else print(\"False\")\n", - "for ### in zip(list1,list2):\n", - " compare(###)\n", - " \n", - "''' " - ] - }, { "cell_type": "markdown", "metadata": {}, @@ -274,14 +335,28 @@ }, { "cell_type": "code", - "execution_count": 12, + "execution_count": 66, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "[('Political Science', 'Essay'), ('Computer Science', 'Homework'), ('Engineering', 'Lab'), ('Mathematics', 'Module')]\n" + ] + } + ], "source": [ "list1 = ['Engineering', 'Computer Science', 'Political Science', 'Mathematics']\n", "list2 = ['Lab', 'Homework', 'Essay', 'Module']\n", "\n", - "# Your code here:\n" + "# Your code here:\n", + "zipped=zip(list1, list2)\n", + "lista3= (list(zipped))\n", + "\n", + "lista3= sorted(lista3, key = lambda x: x[1])\n", + "\n", + "print(lista3)" ] }, { @@ -295,7 +370,7 @@ }, { "cell_type": "code", - "execution_count": 13, + "execution_count": 69, "metadata": {}, "outputs": [], "source": [ @@ -306,15 +381,29 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 70, "metadata": {}, - "outputs": [], - "source": [] + "outputs": [ + { + "data": { + "text/plain": [ + "[('Toyota', 1995), ('Honda', 1997), ('Audi', 2001), ('BMW', 2005)]" + ] + }, + "execution_count": 70, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "d = sorted (d. items(), key = lambda x : x [1])\n", + "d" + ] } ], "metadata": { "kernelspec": { - "display_name": "Python 3", + "display_name": "Python 3 (ipykernel)", "language": "python", "name": "python3" }, @@ -328,7 +417,7 @@ "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", - "version": "3.7.3" + "version": "3.9.7" } }, "nbformat": 4,