code allocates one byte and then overrun it with many #8
Description
char *base = malloc(sizeof(char) * 1);
base[0] = '\0';
strncat(base, hash, hash_length - 1);
1 byte buffer is overwritten by strncat.
{{ message }}
char *base = malloc(sizeof(char) * 1);
base[0] = '\0';
strncat(base, hash, hash_length - 1);
1 byte buffer is overwritten by strncat.