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inf_lb should be inf_lbound? #1258

@IshiguroYoshihiro

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@IshiguroYoshihiro

Should inf_lb be inf_lbound?
When I want to prove a goal that S x -> inf S <= x, I couldn't find inf_lb by searching with (inf _ <= _) or inf "le".

Lemma inf_lb E : has_lbound E -> lbound E (inf E).

Definition lbound A : set T := [set y | forall x, A x -> (y <= x)%O].

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