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Flatten_Binary_Tree_to_Linked_List.cpp
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65 lines (59 loc) · 1.33 KB
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// Source : https://leetcode-cn.com/problems/flatten-binary-tree-to-linked-list/description/
// Number : 114
// Author : HL
// Date : 2018-10-11
// Kill : 95.10%
/**********************************************************************************
Given a binary tree, flatten it to a linked list in-place.
For example, given the following tree:
1
/ \
2 5
/ \ \
3 4 6
The flattened tree should look like:
1
\
2
\
3
\
4
\
5
\
6
**********************************************************************************/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void flatten(TreeNode* root) {
if (root == NULL)
return;
TreeNode *p = root;
while (p != NULL)
{
if (p->left != NULL)
{
TreeNode *lp = p->left;
while (lp->right != NULL)
{
lp = lp->right;
}
lp->right = p->right;
p->right = p->left;
p->left = NULL;
}
p = p->right;
}
return;
}
};