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is_word_pattern.py
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28 lines (28 loc) · 1.17 KB
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def is_word_pattern(pattern, sentence):
"""
Given a pattern and a string str, find if str follows the same pattern.
Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str.
Examples:
- pattern = "abba", str = "dog cat cat dog" should return true.
- pattern = "abba", str = "dog cat cat fish" should return false.
- pattern = "aaaa", str = "dog cat cat dog" should return false.
- pattern = "abba", str = "dog dog dog dog" should return false.
Notes: You may assume pattern contains only lowercase letters, and str contains lowercase letters separated by a single space.
"""
words = sentence.split(' ')
if len(words) != len(pattern):
return False
pattern_match = {}
word_match = {}
for index in range(0, len(words)):
s = pattern[index]
w = words[index]
if s in pattern_match and w in word_match:
if pattern_match[s] != w:
return False
elif s not in pattern_match and w not in word_match:
pattern_match[s] = w
word_match[w] = s
else:
return False
return True