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uniquePathsGrid.java
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65 lines (51 loc) · 1.54 KB
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/*
Given a grid of size m * n, lets assume you are starting at (1,1) and your goal is to reach (m,n). At any instance, if you are on (x,y), you can either go to (x, y + 1) or (x + 1, y).
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1 and 0 respectively in the grid.
Example :
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[
[0,0,0],
[0,1,0],
[0,0,0]
]
The total number of unique paths is 2.
Note: m and n will be at most 100.
*/
public int uniquePathsWithObstacles(ArrayList<ArrayList<Integer>> a) {
if(a.isEmpty() || a==null)
return 0;
int m = a.size();
int n = a.get(0).size();
int [][] dp = new int [m][n];
if(a.get(0).get(0)==1 ||a.get(m-1).get(n-1)==1)
return 0;
for ( int i =0; i<m; i++)
for( int j=0; j<n; j++)
dp[i][j]=0;
for( int i=0; i<m ; i++)
{
if(a.get(i).get(0)==0)
dp[i][0]= 1;
else
break;
}
for( int i=0; i<n ; i++)
{
if(a.get(0).get(i)==0)
dp[0][i]= 1;
else
break;
}
for( int i =1; i<m ;i++)
{
for ( int j =1; j<n;j++)
{
if(a.get(i).get(j)==1)
continue;
else
dp[i][j] = dp[i-1][j]+dp[i][j-1];
}
}
return dp[m-1][n-1];
}