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dfswithstack.cpp
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160 lines (135 loc) · 2.77 KB
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#include <iostream>
using namespace std;
/*
class Stack {
int* arr;
int top;
int size;
public:
Stack(int n) {
size = n;
arr = new int[size];
top = -1;
}
void push(int val) {
if (top < size - 1) {
arr[++top] = val;
}
}
int pop() {
if (top == -1) {
return -1;
}
return arr[top--];
}
bool isEmpty() {
return top == -1;
}
~Stack() {
delete[] arr;
}
};
*/
class Stack{
int *arr;
int top;
int size;
public:
Stack(int n){
size=n;
arr=new int[size];
top=-1;
}
void push(int val){
if(top<size-1){
arr[++top]=val;
}
}
int pop(){
if(top==-1){
return -1;
}else{
return arr[top--];
}
}
bool isEmpty(){
return top==-1;
}
~Stack(){
delete[] arr;
}
};
/*
void dfs(int** adj, int V, int start) {
bool* visited = new bool[V];
for (int i = 0; i < V; i++) {
visited[i] = false;
}
Stack st(V);
st.push(start);
while (!st.isEmpty()) {
int node = st.pop();
if (!visited[node]) {
cout << node << " ";
visited[node] = true;
// Push neighbors in reverse order if you want smaller ones to come first
for (int i = V-1; i >= 0; i--) {
if (adj[node][i] == 1 && !visited[i]) {
st.push(i);
}
}
}
}
delete[] visited;
}
*/
void dfs(int **adj,int vertices,int start){
bool* visited=new bool[vertices];
for(int i=0;i<vertices;i++){
visited[i]=false;
}
Stack st(vertices);
st.push(start);
visited[start]=true;
while(!st.isEmpty()){
int node=st.pop();
cout<<node<<" ";
for(int i=vertices-1;i>=0;i--){
if(adj[node][i]==1 && !visited[i]){
st.push(i);
visited[i]=true;
}
}
}
delete[] visited;
}
int main() {
int V, E;
cout << "Enter number of vertices and edges: ";
cin >> V >> E;
int** adj = new int*[V];
for (int i = 0; i < V; i++) {
adj[i] = new int[V];
for (int j = 0; j < V; j++) {
adj[i][j] = 0;
}
}
cout << "Enter edges (u v):\n";
for (int i = 0; i < E; i++) {
int u, v;
cin >> u >> v;
adj[u][v] = 1;
adj[v][u] = 1; // undirected graph
}
int start;
cout << "Enter starting vertex for DFS: ";
cin >> start;
cout << "DFS Traversal: ";
dfs(adj, V, start);
cout << endl;
for (int i = 0; i < V; i++) {
delete[] adj[i];
}
delete[] adj;
return 0;
}