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How could you assure that result is not caused by larger runtime? #16

@CuriousCat-7

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@CuriousCat-7

According to the paper, The accuracy and runtime by the algorithm in the paper are 74.96 and 79.48 ms,
while the accuracy and runtime by random select are 73.78 ± 0.85 and 77.31 ± 0.9 ms.

Although the paper claim that random search cannot beat the NAS result by accuracy (73.78 + 0.85 = 74.63 < 74.96), how could you assure that result is not caused by larger runtime? For 77.31 + 0.9 = 78.21 ms < 79.48 ms.

If so, we don't need to calculate CE loss. We only need to randomly select a subset of networks according to the desired latency, and choose the best-performed network.

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