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I have a question about the calculation of source signals Y and Z #2

@1DOSAMA

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@1DOSAMA

During the decomposition process, for the first pair, Y(:,1) = X * wt1. As the iteration proceeds to the second pair, Y(:,2) = (X - Driving1) * wt2. So, why is it that after the final decomposition, Y = What.' * X; Z = Vhat.' * X; without taking into account the removal of the driving signal from X during the process?

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