How to escape $ in shell() command so it will not be substituted with empty strings

[piotrekkr]

Hello.

I could not find any info how to escape $ in shell() function. I'm using workaround with passing '$2' as third argument to this function so it will replace $2 with literal $2 but this seems hacky. Here is example:

gotenberg_version := "8.21.1"
gotenberg_image_tag := "gotenberg/gotenberg:" + gotenberg_version + "-cloudrun"
gotenberg_image_sha := shell("docker buildx imagetools inspect $1 | grep '^Digest:' | awk '{print $2}'", gotenberg_image_tag, '$2')

I've tried using \$ or $$ like this:

shell("docker buildx imagetools inspect $1 | grep '^Digest:' | awk '{print \$2}'", gotenberg_image_tag)

shell("docker buildx imagetools inspect $1 | grep '^Digest:' | awk '{print $$2}'", gotenberg_image_tag)

but those do not work. Am I missing something here or is there no way to escape $ in shell command itself?

Thanks.

[laniakea64]

just's shell() function does not have special parsing of the $ character, so however a literal $ does or doesn't need to be escaped is up to the shell. What shell are you using for this justfile?

If you are using a bash-like shell, your original example...

gotenberg_version := "8.21.1"
gotenberg_image_tag := "gotenberg/gotenberg:" + gotenberg_version + "-cloudrun"
gotenberg_image_sha := shell("docker buildx imagetools inspect $1 | grep '^Digest:' | awk '{print $2}'", gotenberg_image_tag, '$2')

... looks like it should work without hacky ways to make the '{print $2}' have a literal $2 😕

[piotrekkr]

You are right. I have no idea what I did wrong that I needed to add this weird stuff with '$2'. I removed it and it works. Most likely it is me being stupid. Thanks for help.