diff --git a/02_activities/assignments/assignment2.sql b/02_activities/assignments/assignment2.sql
index 7dd4f5637..5ad40748a 100644
--- a/02_activities/assignments/assignment2.sql
+++ b/02_activities/assignments/assignment2.sql
@@ -20,11 +20,7 @@ The `||` values concatenate the columns into strings.
 Edit the appropriate columns -- you're making two edits -- and the NULL rows will be fixed. 
 All the other rows will remain the same.) */
 
-SELECT 
-    COALESCE(product_name, '') || ', ' || 
-    COALESCE(product_size, '') || ' (' || 
-    COALESCE(product_qty_type, 'unit') || ')'
-FROM product;
+
 
 --Windowed Functions
 /* 1. Write a query that selects from the customer_purchases table and numbers each customer’s  
@@ -36,53 +32,18 @@ each new market date for each customer, or select only the unique market dates p
 (without purchase details) and number those visits. 
 HINT: One of these approaches uses ROW_NUMBER() and one uses DENSE_RANK(). */
 
-SELECT 
-    customer_id,
-    market_date,
-    ROW_NUMBER() OVER (
-        PARTITION BY customer_id 
-        ORDER BY market_date
-    ) AS visit_number
-FROM customer_purchases;
+
 
 /* 2. Reverse the numbering of the query from a part so each customer’s most recent visit is labeled 1, 
 then write another query that uses this one as a subquery (or temp table) and filters the results to 
 only the customer’s most recent visit. */
-SELECT 
-    customer_id,
-    market_date,
-    ROW_NUMBER() OVER (
-        PARTITION BY customer_id 
-        ORDER BY market_date DESC
-    ) AS reverse_visit_number
-FROM customer_purchases;
-
-
-SELECT *
-FROM (
-    SELECT 
-        customer_id,
-        market_date,
-        ROW_NUMBER() OVER (
-            PARTITION BY customer_id 
-            ORDER BY market_date DESC
-        ) AS reverse_visit_number
-    FROM customer_purchases
-) AS numbered_visits
-WHERE reverse_visit_number = 1;
+
+
 
 /* 3. Using a COUNT() window function, include a value along with each row of the 
 customer_purchases table that indicates how many different times that customer has purchased that product_id. */
 
-SELECT 
-    customer_id,
-    product_id,
-    market_date,
-    quantity,
-    COUNT(*) OVER (
-        PARTITION BY customer_id, product_id
-    ) AS customer_product_purchase_count
-FROM customer_purchases;
+
 
 -- String manipulations
 /* 1. Some product names in the product table have descriptions like "Jar" or "Organic". 
@@ -97,21 +58,10 @@ Remove any trailing or leading whitespaces. Don't just use a case statement for
 Hint: you might need to use INSTR(product_name,'-') to find the hyphens. INSTR will help split the column. */
 
 
-SELECT 
-    product_name,
-    CASE 
-        WHEN INSTR(product_name, '-') > 0 THEN 
-            TRIM(SUBSTR(product_name, INSTR(product_name, '-') + 1))
-        ELSE 
-            NULL
-    END AS description
-FROM product;
 
 /* 2. Filter the query to show any product_size value that contain a number with REGEXP. */
 
-SELECT *
-FROM product
-WHERE product_size REGEXP '[0-9]';
+
 
 -- UNION
 /* 1. Using a UNION, write a query that displays the market dates with the highest and lowest total sales.
@@ -123,41 +73,7 @@ HINT: There are a possibly a few ways to do this query, but if you're struggling
 3) Query the second temp table twice, once for the best day, once for the worst day, 
 with a UNION binding them. */
 
--- Step 1: Calculate total sales per market date
-WITH sales_by_date AS (
-    SELECT 
-        market_date,
-        SUM(quantity * cost_to_customer_per_qty) AS total_sales
-    FROM customer_purchases
-    GROUP BY market_date
-),
-
--- Step 2: Rank the market dates by total sales (descending and ascending)
-ranked_sales AS (
-    SELECT 
-        market_date,
-        total_sales,
-        RANK() OVER (ORDER BY total_sales DESC) AS best_rank,
-        RANK() OVER (ORDER BY total_sales ASC) AS worst_rank
-    FROM sales_by_date
-)
-
--- Step 3: UNION results for best and worst days
-SELECT 
-    'Highest Sales Day' AS label,
-    market_date,
-    total_sales
-FROM ranked_sales
-WHERE best_rank = 1
-
-UNION
 
-SELECT 
-    'Lowest Sales Day' AS label,
-    market_date,
-    total_sales
-FROM ranked_sales
-WHERE worst_rank = 1;
 
 
 /* SECTION 3 */
@@ -172,17 +88,7 @@ Remember, CROSS JOIN will explode your table rows, so CROSS JOIN should likely b
 Think a bit about the row counts: how many distinct vendors, product names are there (x)?
 How many customers are there (y). 
 Before your final group by you should have the product of those two queries (x*y).  */
-SELECT 
-    v.vendor_name,
-    p.product_name,
-    SUM(5 * vi.cost_to_customer_per_qty) AS total_revenue
-FROM vendor_inventory vi
-JOIN vendor v ON vi.vendor_id = v.vendor_id
-JOIN product p ON vi.product_id = p.product_id
-CROSS JOIN (
-    SELECT DISTINCT customer_id FROM customer
-) AS customers
-GROUP BY v.vendor_name, p.product_name;
+
 
 
 -- INSERT
@@ -190,46 +96,20 @@ GROUP BY v.vendor_name, p.product_name;
 This table will contain only products where the `product_qty_type = 'unit'`. 
 It should use all of the columns from the product table, as well as a new column for the `CURRENT_TIMESTAMP`.  
 Name the timestamp column `snapshot_timestamp`. */
-CREATE TABLE product_units AS
-SELECT 
-    *,
-    CURRENT_TIMESTAMP AS snapshot_timestamp
-FROM product
-WHERE product_qty_type = 'unit';
+
 
 
 /*2. Using `INSERT`, add a new row to the product_units table (with an updated timestamp). 
 This can be any product you desire (e.g. add another record for Apple Pie). */
 
-INSERT INTO product_units (
-    product_id, 
-    product_name, 
-    product_size, 
-    product_qty_type, 
-    product_category_id, 
-    snapshot_timestamp
-)
-VALUES (
-    24,                -- Use a unique ID not in use
-    'Pumpkin Pie', 
-    '1 each', 
-    'unit', 
-    3,                  -- Replace with a valid category ID as appropriate
-    CURRENT_TIMESTAMP
-);
+
 
 -- DELETE
 /* 1. Delete the older record for the whatever product you added. 
 
 HINT: If you don't specify a WHERE clause, you are going to have a bad time.*/
 
-DELETE FROM product_units
-WHERE product_id = 7
-  AND snapshot_timestamp < (
-    SELECT MAX(snapshot_timestamp)
-    FROM product_units
-    WHERE product_id = 7
-);
+
 
 -- UPDATE
 /* 1.We want to add the current_quantity to the product_units table. 
@@ -248,20 +128,6 @@ Finally, make sure you have a WHERE statement to update the right row,
 	you'll need to use product_units.product_id to refer to the correct row within the product_units table. 
 When you have all of these components, you can run the update statement. */
 
-ALTER TABLE product_units
-ADD COLUMN current_quantity INT;
-
-UPDATE product_units pu
-SET current_quantity = COALESCE((
-    SELECT vi.quantity
-    FROM vendor_inventory vi
-    WHERE vi.product_id = pu.product_id
-      AND vi.market_date = (
-          SELECT MAX(market_date)
-          FROM vendor_inventory
-          WHERE product_id = pu.product_id
-      )
-    LIMIT 1
-), 0);
+