diff --git a/02_activities/assignments/Assignment1.png b/02_activities/assignments/Assignment1.png
new file mode 100644
index 000000000..853bb0004
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diff --git a/02_activities/assignments/assignment1.sql b/02_activities/assignments/assignment1.sql
index 2e89fa7af..0bcc690d3 100644
--- a/02_activities/assignments/assignment1.sql
+++ b/02_activities/assignments/assignment1.sql
@@ -5,21 +5,28 @@
--SELECT
/* 1. Write a query that returns everything in the customer table. */
-
+SELECT * FROM customer;
/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table,
sorted by customer_last_name, then customer_first_ name. */
-
+SELECT *
+FROM customer
+ORDER BY customer_last_name, customer_first_name
+LIMIT 10;
--WHERE
/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-- option 1
-
+SELECT *
+FROM customer_purchases
+WHERE product_id IN (4, 9);
-- option 2
-
+SELECT *, quantity * cost_to_customer_per_qty AS price
+FROM customer_purchases
+WHERE vendor_id >= 8 AND vendor_id <= 10;
/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty),
filtered by vendor IDs between 8 and 10 (inclusive) using either:
@@ -31,6 +38,9 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
-- option 2
+SELECT *, quantity * cost_to_customer_per_qty AS price
+FROM customer_purchases
+WHERE vendor_id BETWEEN 8 AND 10;
--CASE
@@ -39,19 +49,41 @@ Using the product table, write a query that outputs the product_id and product_n
columns and add a column called prod_qty_type_condensed that displays the word “unit”
if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
-
+SELECT
+ product_id,
+ product_name,
+ CASE
+ WHEN product_qty_type = 'unit' THEN 'unit'
+ ELSE 'bulk'
+ END AS prod_qty_type_condensed
+FROM product;
/* 2. We want to flag all of the different types of pepper products that are sold at the market.
add a column to the previous query called pepper_flag that outputs a 1 if the product_name
contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
-
+SELECT
+ product_id,
+ product_name,
+ CASE
+ WHEN product_qty_type = 'unit' THEN 'unit'
+ ELSE 'bulk'
+ END AS prod_qty_type_condensed,
+ CASE
+ WHEN LOWER(product_name) LIKE '%pepper%' THEN 1
+ ELSE 0
+ END AS pepper_flag
+FROM product;
--JOIN
/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the
vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
-
+SELECT *
+FROM vendor
+INNER JOIN vendor_booth_assignments
+ ON vendor.vendor_id = vendor_booth_assignments.vendor_id
+ORDER BY vendor_name, market_date;
/* SECTION 3 */
@@ -60,7 +92,9 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
/* 1. Write a query that determines how many times each vendor has rented a booth
at the farmer’s market by counting the vendor booth assignments per vendor_id. */
-
+SELECT vendor_id, COUNT(*) AS booth_rentals
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper
sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list
@@ -68,7 +102,16 @@ of customers for them to give stickers to, sorted by last name, then first name.
HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
-
+SELECT
+ c.customer_id,
+ c.customer_first_name,
+ c.customer_last_name,
+ SUM(cp.quantity * cp.cost_to_customer_per_qty) AS total_spent
+FROM customer c
+JOIN customer_purchases cp ON c.customer_id = cp.customer_id
+GROUP BY c.customer_id, c.customer_first_name, c.customer_last_name
+HAVING total_spent > 2000
+ORDER BY c.customer_last_name, c.customer_first_name;
--Temp Table
/* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor:
@@ -81,8 +124,17 @@ When inserting the new vendor, you need to appropriately align the columns to be
-> To insert the new row use VALUES, specifying the value you want for each column:
VALUES(col1,col2,col3,col4,col5)
*/
-
-
+CREATE TEMP TABLE new_vendor AS
+SELECT * FROM vendor;
+
+INSERT INTO temp.new_vendor
+VALUES (
+ 10, -- vendor_id
+ 'Thomass Superfood Store', -- vendor_name
+ 'Fresh Focused', -- vendor_category
+ 'Thomas Rosenthal', -- vendor_owner
+ NULL -- any additional column (e.g. contact_info) if applicable
+);
-- Date
/*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
@@ -90,7 +142,11 @@ VALUES(col1,col2,col3,col4,col5)
HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month
and year are! */
-
+SELECT
+ customer_id,
+ STRFTIME('%m', purchase_date) AS purchase_month,
+ STRFTIME('%Y', purchase_date) AS purchase_year
+FROM customer_purchases;
/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022.
Remember that money spent is quantity*cost_to_customer_per_qty.
@@ -98,3 +154,10 @@ Remember that money spent is quantity*cost_to_customer_per_qty.
HINTS: you will need to AGGREGATE, GROUP BY, and filter...
but remember, STRFTIME returns a STRING for your WHERE statement!! */
+SELECT
+ customer_id,
+ SUM(quantity * cost_to_customer_per_qty) AS total_spent_april_2022
+FROM customer_purchases
+WHERE STRFTIME('%m', purchase_date) = '04'
+ AND STRFTIME('%Y', purchase_date) = '2022'
+GROUP BY customer_id;
\ No newline at end of file
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