What is the expected behavior for play twice

[totty90]

Let's say I have this:

var i = 0;
setInterval(function(){
    omx.play('video' + (i++));
}, 1000)

Videos are longer than 1 second. Let's say for this example that they are 5 seconds long.

The player will (A): plays right away

• Second 0: nothing happens;
• Second 1: omx plays video0;
• Second 2: omx plays video1;

The player will (B): queue incoming videos

• Second 0: nothing happens;
• Second 1: omx plays video0;
• Second 2: omx still plays video0 until ends;
• Second 5: omx plays video1;

The player will (C): doesn't queue incoming videos

• Second 0: nothing happens;
• Second 1: omx plays video0;
• Second 2: omx still plays video0 until ends;
• Second 5: nothing happens

Seems that it works like in case C.

So to make it work the code should be:

var i = 0;
setInterval(function(){
    omx.stop();
    omx.play('video' + (i++));
}, 1000)

Or I have to wait for the stop event to fire before starting again?

I can't test the app, so knowing the behaviour would help me to design the app properly without seeing what happens.

[alepez]

I think the expected behavior is (A). But actually it is (C). I guess it is caused by https://github.com/alessandro-pezzato/omxdirector/blob/v0.1.1/lib/main.js#L175
Because play() awakes a paused video. I will fix it asap.

[totty90]

I use a wrapper on your omxdirector lib and in this I do like this when play is called:

• if playing omx.stop(cb); // the cb is run when omx is stopped

The stop method is like this:

stop: function(cb){
    if(this.__simulationMode){
        cb && cb();
        return;
    }
    this.__omx.once('stop', function(){
        cb && cb();
    });
    this.__omx.stop();
},

Notice how I listen on the stop event once.