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53_MaxSubArray_Simple.py
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71 lines (52 loc) · 2.05 KB
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#-------------------------------------------------------------------------------
#
#-------------------------------------------------------------------------------
# By Will Shin
#
#-------------------------------------------------------------------------------
# LeetCode prompt
#-------------------------------------------------------------------------------
"""
Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
Example:
Input: [-2,1,-3,4,-1,2,1,-5,4],
Output: 6
Explanation: [4,-1,2,1] has the largest sum = 6.
Follow up:
If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
"""
#-------------------------------------------------------------------------------
# Soluton
#-------------------------------------------------------------------------------
"""
* This is somethign very similar to the coin change problem.
* We are comparing teh current node vs the maximum
"""
def my_maxSubarray(nums):
if not nums:
return 0 # edge case with empty array
current_sum = maxSum = nums[0]
for num in nums[1:]:
current_sum = max(num, current_sum + num)
maxSum = max(maxSum, current_sum)
return maxSum
#-------------------------------------------------------------------------------
# Main Leetcode Input Driver
#-------------------------------------------------------------------------------
class Solution(object):
def maxSubArray(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
return my_maxSubarray(nums)
#-------------------------------------------------------------------------------
# Unit Test
#-------------------------------------------------------------------------------
import unittest
class TestSolution(unittest.TestCase):
def test_simple(self):
input = [-2, 1, -3, 4, -1, 2, 1, -5, 4]
ans = 6
self.assertEqual(Solution().maxSubArray(input), ans)
unittest.main()