https://leetcode.com/problems/maximum-ascending-subarray-sum
Given an array of positive integers nums, return the maximum possible sum of an ascending subarray in nums.
A subarray is defined as a contiguous sequence of numbers in an array.
def maxAscendingSum(self, nums: List[int]) -> int:
ans = cur_sum = nums[0]
for x, y in pairwise(nums):
cur_sum = cur_sum + y if x < y else y
ans = max(ans, cur_sum)
return ans int maxAscendingSum(vector<int>& nums) {
int ans = nums[0], curSum = nums[0];
for (int i = 1; i < nums.size(); i++)
{
curSum = (nums[i] > nums[i - 1]) ? curSum + nums[i] : nums[i];
ans = std::max(ans, curSum);
}
return ans;
}