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Solution.java
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96 lines (91 loc) · 2.38 KB
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package stringcompression;
/**
* Given an array of characters, compress it in-place.
*
* The length after compression must always be smaller than or equal to the original array.
*
* Every element of the array should be a character (not int) of length 1.
*
* After you are done modifying the input array in-place, return the new length of the array.
*
*
* Follow up:
* Could you solve it using only O(1) extra space?
*
*
* Example 1:
*
* Input:
* ["a","a","b","b","c","c","c"]
*
* Output:
* Return 6, and the first 6 characters of the input array should be: ["a","2","b","2","c","3"]
*
* Explanation:
* "aa" is replaced by "a2". "bb" is replaced by "b2". "ccc" is replaced by "c3".
*
*
* Example 2:
*
* Input:
* ["a"]
*
* Output:
* Return 1, and the first 1 characters of the input array should be: ["a"]
*
* Explanation:
* Nothing is replaced.
*
*
* Example 3:
*
* Input:
* ["a","b","b","b","b","b","b","b","b","b","b","b","b"]
*
* Output:
* Return 4, and the first 4 characters of the input array should be: ["a","b","1","2"].
*
* Explanation:
* Since the character "a" does not repeat, it is not compressed. "bbbbbbbbbbbb" is replaced by "b12".
* Notice each digit has it's own entry in the array.
*
*
* Note:
*
* All characters have an ASCII value in [35, 126].
* 1 <= len(chars) <= 1000.
*/
class Solution {
/**
* Time: O(N), N is length of chars
* Space: O(1), no extra space is used
*
* Runtime: 1 ms, faster than 92.75% of Java online submissions for String Compression.
* Memory Usage: 38.8 MB, less than 6.82% of Java online submissions for String Compression.
*
*/
int compress(char[] chars) {
if(chars.length == 1) return 1;
int i = 0, j = i+1, count = 1, writePos = 0;
String countStr = "";
while(writePos < chars.length) {
while(j < chars.length && chars[i] == chars[j]) {
j++; count++;
}
// write count only if > 1
chars[writePos++] = chars[i];
if(count > 1) {
countStr = String.valueOf(count);
for(char c: countStr.toCharArray()) {
chars[writePos++] = c;
}
}
if(j >= chars.length)
break;
i = j;
j = i+1;
count = 1;
}
return writePos;
}
}