diff --git a/BuildingBlocks/some problem lesson 3.js b/BuildingBlocks/some problem lesson 3.js
index 8193788..b73e5a3 100644
--- a/BuildingBlocks/some problem lesson 3.js	
+++ b/BuildingBlocks/some problem lesson 3.js	
@@ -1,21 +1,23 @@
-//==========================================================
-//------------------------Problem09-------------------------
-//==========================================================
-lesson 5 change on my own Anabelle
-Sam Smith
-Add something here
 /*
-Write a function, intersection, that takes two arrays and returns a new array containing 
-only the values that are in both arrays.
-a:  check array 1 elements against array 2
- i: two or more arrays
-o: a union or intersection of shared elements
-e: one array might be longer than the other
+Write a function, transformAndRepeat that takes a string, a transformer function, 
+and a number, and returns the result of invoking the transformer function with the string, repeated number times.
+See the tests for additional examples.
+My personal notes:
+i = string, a helper function, and number, n.
+o = a string, repeated n times
+a = 
+e = the string may be all caps or mix of upper/lower case, it may contain more than one word.
+the first "letter" may not be a letter at all, but a #. does that matter?
+the helper function (or functions) must be capable of performing different operations
+    1. converting all chars to lowercase
+    2. only repeating 1st char
+    3. need to append/concatenate char to end of a string
 */
 function intersection (array1, array2) {
 
 
 
 
-//intersection(['a', 'b', 'c', 'f', 'g'], ['d', 'b', 'c', 'd', 'e'])); // --> ['b', 'c']
-intersection([1, 4, 6, 2], [10, 9, 4, 1, 5, 6]); // --> [1, 4, 6]
\ No newline at end of file
+console.log(transformAndRepeat('HELLO', lowerCase, 3)); // --> 'hellohellohello'
+console.log(transformAndRepeat('doggo', firstLetter, 6)); // --> 'dddddd'
+console.log(transformAndRepeat('hi', exclaim, 4)); // --> 'hi! hi! hi! hi! 
\ No newline at end of file
diff --git a/HREXT/Problem 10 strategy.js b/HREXT/Problem 10 strategy.js
new file mode 100644
index 0000000..01186c2
--- /dev/null
+++ b/HREXT/Problem 10 strategy.js	
@@ -0,0 +1,37 @@
+/*
+Write a function, transformAndRepeat that takes a string, a transformer function, 
+and a number, and returns the result of invoking the transformer function with the
+ string, repeated number times.
+
+My personal notes:
+i = string, a helper function, and number, n.
+o = a string, repeated n times
+a = the helper function (or functions) need to support performing different operations on given string
+e = the string may be all caps or mix of upper/lower case, it may contain more than one word.
+    the first "letter" may not be a letter at all, but a #. does that matter?
+
+tranformation requirements:
+    1. convert all chars to lowercase
+    2. only repeating 1st char
+    3. append/concatenate char to end of passed-in string, then repeat
+*/
+function transformAndRepeat (str, transformReq, num) {
+
+/*two actions for potential helper function(s)
+    1.  3 transform types
+        observation 1:  because each scenario applies repitition in different ways (e.g. to first char, to end of string, to all chars of string),
+                        plan to first apply transformation requirement to string, then apply repetition.
+        observation 2:  should consider writing code such that additional transform types can easily be added later?
+        efficiency:     b/c each transform type is unique, what approach performs more optimally? 
+                        approach1:  use if ... else. as in, if (str action === lowercase), //do something 
+                        approach2:  do seperate helper functions for each transform req/scenario
+                        approach-n: ... or some other better approach?
+    2. repeat num times  
+        a. Initially wondered whether .push or other method allows me to repeat the same action to a given data type/string num times.
+        b. After researching found array.fill(value,start,end) that I thought I'd try
+
+}
+*/
+console.log(transformAndRepeat('HELLO', lowerCase, 3)); // --> 'hellohellohello'
+console.log(transformAndRepeat('doggo', firstLetter, 6)); // --> 'dddddd'
+console.log(transformAndRepeat('hi', exclaim, 4)); // --> 'hi! hi! hi! hi! 
\ No newline at end of file
diff --git a/Immersive_Readiness/Practice Problem from Steve for Interview.js b/Immersive_Readiness/Practice Problem from Steve for Interview.js
new file mode 100644
index 0000000..6ffe470
--- /dev/null
+++ b/Immersive_Readiness/Practice Problem from Steve for Interview.js	
@@ -0,0 +1,88 @@
+//1. Write a function 'getBirthday' which takes in an object with year, day, and month properties, and returns a string with the month and day separated by a space.
+
+var getBirthday = function(obj) {      //created function get b-day that takes in an obj
+    return obj.month + " " + obj.day;  //expression that concatentates obj month and day
+}
+
+//Sample input:
+var birthdayA = {
+    year: 2010, 
+    day: 19, 
+    month: "September"
+};
+var birthdayB = {
+    year: 1950, 
+    day: 20, 
+    month: "December"
+};
+
+getBirthday(birthdayA); //"September 19"  // call getBirthday function passing in argument B-day A object
+// getBirthday(birthdayB); //"December 20"
+
+
+/*2. Write a function which accepts an array of numbers and a target number. 
+This function should return a new array of all numbers from the input array 
+which are less than or equal to the input target number.*/
+
+
+var getNumbersLessThan = function(numbersArr, targetNum) {
+    var newArray = [];
+    for (var i = 0; i < numbersArr.length; i ++) {
+        if(numbersArr[i] <= targetNum) {
+            newArray.push(numbersArr[i]);
+        }
+    }
+    return newArray;
+}
+var inputArray = [10, 22, 24, 19, 4, 25];
+//var inputTargetNumA = 25;
+var inputTargetNumB = 10;
+
+var output = getNumbersLessThan(inputArray, inputTargetNumB); //for A [10, 22, 24, 25]
+//getNumbersLessThan(inputArray, inputTargetNumB); // for B[10, 4]
+console.log(output);
+
+
+/*3. You are asked by the head of Human Resources to compile a list of birthdays 
+in a given month. Write a function which accepts an array with a structure similar 
+to "birthdayCollection", as well as a month. Name this function "birthdaysInMonth"; 
+it should return an array of strings with a Month and Day separated by a white space.
+
+o:  a new array with Month and Day for all elements within the birthday Month provided
+i:  an array of objects, need to go through each object's elements
+*/
+var birthdayCollection = [ 
+    { year: 1982, day: 10, month: 'February' },
+    { year: 1966, day: 22, month: 'March' },
+    { year: 2008, day: 19, month: 'December' },
+    { year: 1963, day: 3, month: 'March' },
+    { year: 2000, day: 7, month: 'February' },
+    { year: 1977, day: 18, month: 'February' } 
+];
+
+var birthdaysInMonth = function(birthdayObjs, birthdayMonth) {
+    var newBirthdayArray = [];
+    for (var i = 0; i < birthdayObjs.length; i ++) { 
+        if (birthdayObjs[i].month === birthdayMonth) {
+            newBirthdayArray.push(birthdayObjs[i].month + " " + birthdayCollection[i].day)
+        }
+    }
+    return newBirthdayArray;
+}
+var output = birthdaysInMonth(birthdayCollection, "February"); //[ 'February 10', 'February 7', 'February 18' ]
+console.log(output);
+
+//4. write a function that takes in two integers and computes the sum between them
+var computeSumBetween = (num1, num2) => {  //function that takes in two integrers
+    if (num1 > num2) {                     //addressing exception where num1 is greater than two
+        return 0;
+    }
+    let sum = 0;                           //est. var sum to store total while looping thru delta btw nums
+    for (let i = num1; i < num2; i++) {
+        sum += i;
+    }
+    return sum;
+};
+
+var output = computeSumBetween(2,5);        //calling function and passing in arguments (two integers)
+console.log(output);