remove_curly will be broken in 1.6

[KristofferC]

In 1.6, Vector{T} prints as Vector{T} instead of Array{T, 1} which breaks remove_curly. Relying on the string representation like this is kinda brittle.

[JeffBezanson]

Similarly, get_curly can just be T.parameters.

[JeffBezanson]

remove_curly can be T.name.wrapper.

[mmider]

Thanks a lot, I'll update the code accordingly soon.