diff --git a/lesson-1/huyong/fanpai.c b/lesson-1/huyong/fanpai.c
new file mode 100644
index 0000000..f0f7c2f
--- /dev/null
+++ b/lesson-1/huyong/fanpai.c
@@ -0,0 +1,91 @@
+#include<stdio.h>
+#include <stdlib.h>
+#include <windows.h>
+#include<time.h>
+void shuchuint(char a[4][4])
+{
+	int i,j;
+	for(i=0;i<4;i++)
+	{
+	for(j=0;j<4;j++) {printf("%2c",a[i][j]);}
+	printf("\n");
+	}
+}
+int panduan(char a[4][4])
+{
+	int i,j,s=1;
+	for(i=0;i<4;i++)
+	{	
+		for(j=0;j<4;j++)
+		{
+		if(a[i][j]=='*')
+		s=0;
+		break;
+		}
+		
+	}
+	return s;
+}
+int main()
+{
+	int i,j,x1,y1,x2,y2,k=0,m,n,s;	
+	char a[4][4]={'*','*','*','*','*','*','*','*','*','*','*','*','*','*','*','*'};
+	char c[16]={'2','8','7','1','1','6','7','8','4','2','3','6','4','3','5','5'};
+	char b[4][4];
+	printf("这是一个锻炼记忆力的翻牌游戏！\n一开始有10s的时间观察随机产生的4x4矩阵。其后输入坐标进行翻牌，数字相同则翻牌成功.\nHave a try！\n");
+	printf("******************************************************************\n");
+	printf("按下回车，游戏开始！");
+	while(getchar()==10)
+	{
+		srand((unsigned)time(NULL));
+		for(i=0;i<1000;i++)
+		{
+			m=rand()%16;
+			n=rand()%16;
+			s=c[m];
+			c[m]=c[n];
+			c[n]=s;
+		}
+		for(i=0;i<4;i++)
+		{
+		for(j=0;j<4;j++)
+		{
+			b[i][j]=c[k];
+			k++;
+		}
+		}
+		shuchuint(b);
+		Sleep(5000);
+		system("cls");
+		shuchuint(a);
+		while(panduan(a)==0)
+		{
+			lab1:
+			printf("x1= ,y1= (1~4)\t");scanf("%d%d",&x1,&y1);
+			if(!(x1>=1&&x1<=4)||!(y1>=1&&y1<=4)) {printf("请正确输入！"); goto lab1;}
+			printf("\nx2= ,y2= (1~4)\t");scanf("%d%d",&x2,&y2);
+			lab2:
+			if(!(x2>=1&&x2<=4)||!(y2>=1&&y2<=4)) {printf("请正确输入！"); goto lab2;}
+			if(b[x1-1][y1-1]==b[x2-1][y2-1])
+			{
+			a[x1-1][y1-1]=b[x1-1][y1-1];
+			a[x2-1][y2-1]=b[x2-1][y2-1];
+			shuchuint(a);
+			printf("正确，Go on！\n");
+			}
+			else
+			{
+				a[x1-1][y1-1]=b[x1-1][y1-1];
+				a[x2-1][y2-1]=b[x2-1][y2-1];
+				shuchuint(a);
+				printf("不正确哟！");
+				Sleep(2000);
+				system("cls");
+				a[x1-1][y1-1]='*';
+				a[x2-1][y2-1]='*';
+				shuchuint(a);
+			}
+		}
+		printf("U Win！！");
+	}
+}
\ No newline at end of file
diff --git a/lesson-1/huyong/fanpai.md b/lesson-1/huyong/fanpai.md
new file mode 100644
index 0000000..1527365
--- /dev/null
+++ b/lesson-1/huyong/fanpai.md
@@ -0,0 +1,37 @@
+翻牌游戏
+===========
+
+
+
+翻牌
+===
+---
+
+问题描述
+------
+
+- 游戏初始:
+现在有一个4*4的矩阵，存储两组1~8数字。起始时，会有两秒的时间观察数字在矩阵的位置，之后每个点则处于未翻开状态
+
+
+- 游戏过程:
+每次翻开两个点，如果相同，则成功翻开（图1），输出翻开后的矩阵；如果不同，则翻开失败(图2)，等待1s后输出保持翻开前的矩阵。直到全部翻开为成功（图片3）.  
+![alt 图片1](C:\Users\acer\Desktop\fanpai\图片1)
+![alt 图片2]（C:\Users\acer\Desktop\fanpai\图片2)
+![alt 图片3]（C:\Users\acer\Desktop\fanpai\图片3)
+
+
+- 游戏操作:
+输入：每次输入四个1~8的整数，作为（x1,y1）（x2,y2）即翻开的两个点的坐标
+
+   
+游戏编程:
+----
+-见： http://1013975672.qzone.qq.com
+
+
+编程难点
+----
+- 将一个二维数组乱序
+- 清屏函数
+-屏幕暂停函数
\ No newline at end of file
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