diff --git a/SELECT_SQL.sql b/SELECT_SQL.sql
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+ USE sakila;
+
+-- How many distinct (different) actors' last names are there?
+
+ SELECT COUNT(DISTINCT last_name) AS distinct_last_names
+ from actor;
+ 
+ -- In how many different languages where the films originally produced? (Use the column `language_id` from the `film` table)
+ 
+SELECT COUNT(DISTINCT language_id) AS different_languages
+FROM film;
+
+-- How many movies were released with `"PG-13"` rating?
+SELECT COUNT(*) as PG_13
+FROM FILM
+WHERE RATING = 'PG-13';
+
+-- Get 10 the longest movies from 2006.
+
+SELECT title, length, release_year
+FROM film
+WHERE release_year = 2006
+ORDER BY length DESC
+LIMIT 10;
+
+-- How many days has been the company operating (check `DATEDIFF()` function)?
+
+select DATEDIFF(max(return_date), min(rental_date))
+from rental;
+
+-- 6. Show rental info with additional columns month and weekday. Get 20.
+
+SELECT rental_id, rental_date, 
+       MONTH(rental_date) AS month,
+       dayname(rental_date) AS weekday
+FROM rental
+LIMIT 20;
+
+-- 7. Add an additional column `day_type` with values 'weekend' and 'workday' depending on the rental day of the week. *******
+
+select *, 
+IF(dayofweek(rental_date)<= 5, "work", "weekend") as day_type from rental;
+
+-- 8. How many rentals were in the last month of activity? ****
+
+select year(rental_date) as year_r, month(rental_date) as month_r,count(rental_id) 
+from rental 
+group by year(rental_date),month(rental_date)
+order by year(rental_date) desc,month(rental_date) desc
+limit 1;
+
+-- 9. Get film ratings.
+
+select rating,count(rating) as numfilms from film
+group by rating
+order by numfilms desc;
+
+-- 10. Get release years.
+
+select release_year,count(release_year) as numfilms from film
+group by release_year
+order by numfilms desc;
+
+-- 11. Get all films with ARMAGEDDON in the title.
+
+select * 
+from film
+where title like "%armageddon%";
+
+-- 12. Get all films with APOLLO in the title
+
+select *
+from film
+where title like "%Apollo%";
+
+-- 13. Get all films which title ends with APOLLO.
+
+select *
+from film
+where title like"%Apollo";
+
+-- 14. Get all films with word DATE in the title.
+
+select *
+from film
+where title like '%date%';
+
+-- 15. Get 10 films with the longest title.
+
+select title
+from film
+order by length(title) desc
+limit 10;
+
+-- 16. Get 10 the longest films.
+
+select title, length
+from film
+order by length desc
+limit 10;
+
+-- 17. How many films include **Behind the Scenes** content?
+
+SELECT COUNT(*) as behind_scenes
+FROM FILM
+WHERE special_features like '%Behind the scenes%';
+
+-- 18. List films ordered by release year and title in alphabetical order.
+
+select title, release_year
+from film
+order by release_year, title;
+
+-- 19. Drop column `picture` from `staff`.
+
+alter table staff
+drop column picture;
+
+
+-- 20. A new person is hired to help Jon. Her name is TAMMY SANDERS, and she is a customer. Update the database accordingly.
+
+select * from customer
+where first_name = 'Tammy' and last_name='Sanders';
+
+INSERT INTO staff (staff_id, first_name, last_name, address_id, email, store_id, active, username, password, last_update)
+values (3, "tammy", "sanders", 79, "TAMMY.SANDERS@sakilacustomer.org", 2, 1,  "Tammy", null, "2006-02-15 04:57:20");
+
+-- 21. Add rental for movie "Academy Dinosaur" by Charlotte Hunter from Mike Hillyer at Store 1.
+
+
+insert into rental (rental_date, inventory_id, customer_id, staff_id) values
+((current_date()),
+(select max(inventory_id) from inventory where film_id = (select max(film_id) from film where title = "Academy Dinosaur") and store_id = 1) ,
+(select customer_id from customer where first_name = 'CHARLOTTE' and last_name = 'HUNTER'),
+(select staff_id from staff where first_name = 'MIKE' and last_name = 'HILLYER')
+);
+
+
+
+
+-- 22. Delete non-active users, but first, create a _backup table_ `deleted_users` to store `customer_id`, `email`, and the `date` for the users that would be deleted. Follow these steps:
+
+--    - Check if there are any non-active users
+--    - Create a table _backup table_ as suggested
+--   - Insert the non active users in the table _backup table_
+--    - Delete the non active users from the table _customer_
+
+select * from customer where active = 0; -- 15 non active customers
+
+	-- Create a table backup table as suggested
+	-- Insert the non active users in the table backup table
+create table deleted_users as select customer_id, email, current_date() from customer where active = 0;
+
+	-- Delete the non active users from the table customer
+delete from customer where active = 0;
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