From e9246352686a9315e6501e538c493f4162750dd9 Mon Sep 17 00:00:00 2001
From: foscanit <clauprelat@gmail.com>
Date: Wed, 25 Oct 2023 20:02:39 +0200
Subject: [PATCH] =?UTF-8?q?[Cl=C3=A0udia=20Pintos]=20lab-mysql-select?=
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---
 queries_shakira.sql | 177 ++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 177 insertions(+)
 create mode 100644 queries_shakira.sql

diff --git a/queries_shakira.sql b/queries_shakira.sql
new file mode 100644
index 0000000..34dc93e
--- /dev/null
+++ b/queries_shakira.sql
@@ -0,0 +1,177 @@
+USE SAKILA;
+
+-- 1. How many distinct (different) actors' last names are there? 21
+SELECT COUNT(distinct(last_name)) FROM actor;
+
+-- 2. In how many different languages where the films originally produced? (Use the column `language_id` from the `film` table)
+SELECT COUNT(distinct(language_id)) 
+	FROM film;
+-- Answer: 1 original language
+
+-- 3. How many movies were released with `"PG-13"` rating? 223
+SELECT COUNT(rating)
+	FROM film
+		WHERE rating = "PG-13";
+
+-- 4. Get 10 the longest movies from 2006.
+SELECT title, length 
+	FROM film
+		ORDER by length DESC LIMIT 10; 
+-- 5. How many days has been the company operating (check `DATEDIFF()` function)?rental_id
+SELECT DATEDIFF(NOW(), MIN(rental_date)) 
+	FROM rental;
+-- 6. Show rental info with additional columns month and weekday. Get 20.
+SELECT *,
+       MONTH(return_date) AS return_month,
+       DAYOFWEEK(return_date) AS return_weekday
+FROM rental
+LIMIT 20;
+
+-- 7. Add an additional column `day_type` with values 'weekend' and 'workday' depending on the rental day of the week.
+alter table rental add day_type varchar(20);
+SET SQL_SAFE_UPDATES=0;
+update rental
+	set day_type = case
+		WHEN DAYOFWEEK(rental_date) IN (1, 7) THEN 'weekend'
+		ELSE 'workday'
+	END; 
+SET SQL_SAFE_UPDATES=1;
+
+
+
+-- 8. How many rentals were in the last month of activity?
+SELECT MAX(rental_date)
+	from rental;
+    
+SELECT COUNT(rental_date) 
+from rental
+where rental_date between "2006-02-01" and "2006-03-01";
+
+-- 9. Get film ratings.
+SELECT distinct(rating)
+FROM film;
+
+-- 10. Get release years.
+SELECT distinct(release_year)
+from film;
+
+-- 11. Get all films with ARMAGEDDON in the title.
+select *
+from film
+where title like "%ARMAGEDDON%";
+
+-- 12. Get all films with APOLLO in the title
+SELECT title
+from film
+where title like "%APOLLO%";
+
+-- 13. Get all films which title ends with APOLLO.
+SELECT title
+from film
+where title like "%APOLLO"; 
+
+-- 14. Get all films with word DATE in the title.
+SELECT title
+from film
+where title like "%DATE%";
+
+-- 15. Get 10 films with the longest title.
+SELECT title, char_length(title)
+from film
+order by char_length(title) DESC 
+limit 10;
+
+-- 16. Get 10 the longest films.
+select title, length
+from film
+order by length DESC
+limit 10;
+
+-- 17. How many films include **Behind the Scenes** content?
+SELECT title
+from film
+where special_features like "%behind the scenes%";
+
+-- 18. List films ordered by release year and title in alphabetical order.
+SELECT title, release_year
+from film
+order by release_year, title;
+
+-- 19. Drop column `picture` from `staff`.
+alter table staff
+drop column picture;
+
+-- 20. A new person is hired to help Jon. Her name is TAMMY SANDERS, and she is a customer. Update the database accordingly.
+select *
+from customer
+where first_name like "tammy";
+
+INSERT INTO staff (first_name, last_name, address_id, email, store_id, active, last_update, username, password)
+SELECT first_name, last_name, address_id, email, store_id, active, NOW(), 'tammys', 'password123'
+FROM customer
+WHERE first_name = 'TAMMY' AND last_name = 'SANDERS';
+
+select *
+from staff;
+
+-- 21. Add rental for movie "Academy Dinosaur" by Charlotte Hunter from Mike Hillyer at Store 1. You can use current date for the `rental_date` column in the `rental` table.
+select film_id
+from film
+where title = "academy dinosaur";
+
+select max(inventory_id)
+from inventory
+where film_id = "1" and store_id = "1";
+
+select customer_id
+from customer
+where first_name = "Charlotte" and last_name = "Hunter";
+
+select staff_id
+from staff
+where first_name = "Mike" and last_name = "Hillyer";
+
+select rental_id
+from rental
+where inventory_id = "4" and customer_id = "130";
+
+select *
+from rental;
+
+SET SQL_SAFE_UPDATES=0;
+INSERT INTO rental (rental_date, inventory_id, customer_id, staff_id, last_update, day_type)
+values (current_date, 4, 130, 1, now(), case WHEN DAYOFWEEK(current_date) IN (1, 7) THEN 'weekend' ELSE 'workday' end);
+SET SQL_SAFE_UPDATES=1;
+
+select *
+from rental
+where inventory_id = "4" and customer_id = "130";
+
+-- 22. Delete non-active users, but first, create a _backup table_ `deleted_users` to store `customer_id`, `email`, and the `date` for the users that would be deleted. Follow these steps:
+select count(active)
+from customer
+where active = "0";
+
+CREATE TABLE DELETED_USERS (
+    customer_id INT,
+    email VARCHAR(250),
+    deleted_date date
+    );
+    
+    
+INSERT INTO deleted_users (customer_id, email, deleted_date)
+SELECT customer_id, email, current_date
+FROM customer
+WHERE active = "0";
+
+select *
+from deleted_users;
+
+delete from customer
+where active = 0;
+
+
+
+
+
+    
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