Week3_PQuiz_WhileLoops.py

#Question 2
#Fill in the blanks to make the print_prime_factors function print all the prime factors of a number. A prime factor is a number that is prime and divides another without a remainder.

def print_prime_factors(number):
  # Start with two, which is the first prime
  factor = 2
  # Keep going until the factor is larger than the number
  while factor <= number:
    # Check if factor is a divisor of number
    if number % factor == 0:
      # If it is, print it and divide the original number
      print(factor)
      number = number / factor
    else:
      # If it's not, increment the factor by one
      factor += 1
    return "Done"
  
  print_prime_factors(100)
  # Should print 2,2,5,5,
  # DO NOT DELETE THIS COMMENT
  
 #Question 3
 #The following code can lead to an infinite loop. Fix the code so that it can finish successfully for all numbers
  #Note: Try running your function with the number 0 as the input, and see what you get
  
 def is_power_of_two(n):
  #Check if the number can be divided by two without the remainder
  While n % 2 == 0 and n != 0:
    n = n / 2
  #If after dividing by two the number is 1, it's a power of two.
  if n == 1:
    return True
  return False

print(is_power_of_two(0)) # Should be False
print(is_power_of_two(1)) # Should be True
print(is_power_of_two(8)) # Should be True
print(is_power_of_two(9)) # Should be False

#Question 4
#Fill in the empty function so that it returns the sum of all the divisors of a number, without including it. 
#A divisor is a number that divides into another without a remainder.
def sum_divisors(n):
  i = 1                   #initialize value
  sum = 0
  while i < n:   
    if n % i == 0:
      sum += i
      i += 1
     else:
      i += 1
  return sum

print(sum_divisors(0))
# 0
print(sum_divisors(3)) # Should sum of 1
# 1
print(sum_divisors(36)) # Should sum of 1+2+3+4+6+9+12+18
# 55
print(sum_divisors(102)) # Should be sum of 2+3+6+17+34+51
# 114

#Question 5
# The multiplication_table function prints  the results of a number passed to it multiplied by 1 through 5.
# An additional requirement is that the result is not to exceed 25, which is done with the break statement.
# Fill in the blanks to complete the function to satisfy these conditions.

def multiplication_table(number):
  # Initialize the starting point of the multiplication table
  multiplier = 1
  # Only want to loop through 5
  while multiplier <= 5: 
    result = number*multiplier
    # What is the additional condition to exit out of the loop?
    if result>25:
      break
    print(str(number) + "x" + str(multiplier) + "=" + str(result))
    # Increment the variable for the loop
    multiplier += 1
    
   multiplication_table(3) 
# Should print: 3x1=3 3x2=6 3x3=9 3x4=12 3x5=15

multiplication_table(5) 
# Should print: 5x1=5 5x2=10 5x3=15 5x4=20 5x5=25

multiplication_table(8)	
# Should print: 8x1=8 8x2=16 8x3=24