diff --git a/02_activities/assignments/Assignment_one_SQL.drawio.png b/02_activities/assignments/Assignment_one_SQL.drawio.png
new file mode 100644
index 000000000..8826a84d7
Binary files /dev/null and b/02_activities/assignments/Assignment_one_SQL.drawio.png differ
diff --git a/02_activities/assignments/assignment1.sql b/02_activities/assignments/assignment1.sql
index 2e89fa7af..a097d4bec 100644
--- a/02_activities/assignments/assignment1.sql
+++ b/02_activities/assignments/assignment1.sql
@@ -4,21 +4,29 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
+SELECT*
+FROM customer;
 
 
-
-/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
+/* 2. Write a query that displays all of the columns and 10 rows from the customer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
+SELECT*
+FROM customer
+ORDER BY customer_last_name, customer_first_name
+LIMIT 10;
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 -- option 1
-
+SELECT*
+FROM customer_purchases
+WHERE product_id='4' or	product_id='9';
 
 -- option 2
-
+SELECT*
+FROM customer_purchases
+WHERE product_id IN (4,9);
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -27,10 +35,17 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
+SELECT*, 
+quantity*cost_to_customer_per_qty as price
+FROM customer_purchases
+WHERE vendor_id >=8 AND vendor_id <=10;
 
 
 -- option 2
-
+SELECT*, 
+quantity*cost_to_customer_per_qty as price
+FROM customer_purchases
+WHERE vendor_id BETWEEN 8 AND 10;
 
 
 --CASE
@@ -38,19 +53,39 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
-
+SELECT 
+product_id,
+product_name,
+	CASE WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+	END as product_qty_type_condensed
+FROM product;
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
+SELECT 
+product_id,
+product_name,
+	CASE WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+	END as product_qty_type_condensed,
+	CASE WHEN product_name LIKE '%pepper%' THEN 1
+	ELSE 0
+	END as pepper_flag
+FROM product;
 
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
-
+SELECT* 
+FROM vendor_booth_assignments as vba
+INNER JOIN vendor as v
+	ON vba.vendor_id = v.vendor_id
+ORDER BY vendor_name,market_date;
 
 
 
@@ -59,7 +94,11 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 -- AGGREGATE
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
-
+SELECT 
+count(booth_number) AS total_booths_rented,
+vendor_id
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
 
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
@@ -67,6 +106,18 @@ sticker to everyone who has ever spent more than $2000 at the market. Write a qu
 of customers for them to give stickers to, sorted by last name, then first name. 
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
+SELECT 
+c.customer_first_name,
+c.customer_last_name,
+SUM(quantity*cost_to_customer_per_qty) as total_spend
+FROM customer_purchases as cp
+LEFT JOIN customer as c
+	ON cp.customer_id=c.customer_id
+GROUP BY cp.customer_id
+HAVING total_spend>=2000
+ORDER BY c.customer_last_name,c.customer_first_name;
+
+
 
 
 
@@ -82,7 +133,23 @@ When inserting the new vendor, you need to appropriately align the columns to be
 VALUES(col1,col2,col3,col4,col5) 
 */
 
+--drop table if needed
+DROP TABLE IF EXISTS temp.new_vendor;
+
+--creating temp table
+CREATE TABLE temp.new_vendor AS
 
+--defining temp table 
+SELECT*
+FROM vendor;
+
+--adding 10th vendor to temp.new_vendor
+INSERT INTO temp.new_vendor (vendor_id,vendor_name,vendor_type,vendor_owner_first_name,vendor_owner_last_name)
+VALUES (10,"Thomas' Superfood Store",'Fresh Focused','Thomas','Rosenthal');
+
+--verifying it worked
+SELECT *
+FROM temp.new_vendor;
 
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
@@ -90,6 +157,10 @@ VALUES(col1,col2,col3,col4,col5)
 HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
 and year are! */
 
+SELECT customer_id,
+strftime('%m',market_date) AS 'Month' ,strftime('%Y',market_date) AS 'Year'
+FROM customer_purchases;
+
 
 
 /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
@@ -98,3 +169,11 @@ Remember that money spent is quantity*cost_to_customer_per_qty.
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
 
+SELECT 
+customer_id,
+strftime('%m',market_date) AS 'Month', 
+strftime('%Y',market_date) AS 'Year',
+quantity*cost_to_customer_per_qty AS total_spend
+FROM customer_purchases
+WHERE Month = '04' AND Year = '2022'
+GROUP BY customer_id;