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day3.js
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98 lines (92 loc) · 2.01 KB
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// Task 1---> number is +ve,0 or -ve
let num = -5;
if (num > 0)
console.log(num + " is positive");
else if (num === 0)
console.log(num + " is zero")
else
console.log(num + " is negative");
// Task2----> Voting eligibility
let age = 17;
if (age >= 18)
console.log("person is eligible to vote");
else
console.log("person is NOT eligible to vote");
// Task 3----> largest out of 3 numbers
let num1 = 34;
let num2 = 34;
let num3 = 30;
if (num1 >= num2) {
if (num1 >= num3)
console.log(num1 + " is largest");
else // num1<num3
console.log(num3 + " is largest");
}
else // num2>num1
{
if (num2 >= num3)
console.log(num2 + " is largest");
else // num2<num3
console.log(num3 + " is largest");
}
// Task 4----> tell day of week based on day no(1-7)
let day = 5;
switch (day) {
case 1:
console.log("SUNDAY");
break;
case 2:
console.log("MONDAY");
break;
case 3:
console.log("TUESDAY");
break;
case 4:
console.log("WEDNESDAY");
break;
case 5:
console.log("THURSDAY");
break;
case 6:
console.log("FRIDAY");
break;
case 7:
console.log("SATURDAY");
break;
default:
console.log("INVALID DAY");
}
//Task 5----> grading using switch-case
let score = 45;
switch (Math.floor(score / 10)) {
case 10:
case 9:
console.log('A');
break;
case 8:
console.log('B');
break;
case 7:
console.log('C');
break;
case 6:
console.log('D');
break;
case 5:
console.log('E');
break;
default:
console.log('F');
}
//Task 6----> odd or even number using ternary operator
let n = 5;
let result = n % 2 == 0 ? n + " is even" : n + " is odd";
console.log(result);
//Task 7----> yr is leap yr or not
let yr = 1900;
if (yr % 4 == 0 && (yr % 100 != 0 || yr % 400 == 0)) {
console.log(yr + " is a leap year");
}
else {
console.log(yr + " is not a leap year");
}