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[level 3] Title: 즐겨찾기가 가장 많은 식당 정보 출력하기, Time: 0.00 ms, Memory: 0.0 MB -BaekjoonHub
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# [level 3] 즐겨찾기가 가장 많은 식당 정보 출력하기 - 131123
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[문제 링크](https://school.programmers.co.kr/learn/courses/30/lessons/131123)
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### 성능 요약
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메모리: 0.0 MB, 시간: 0.00 ms
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### 구분
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코딩테스트 연습 > GROUP BY
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### 채점결과
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Empty
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### 제출 일자
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2025년 11월 10일 11:50:27
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### 문제 설명
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<p>다음은 식당의 정보를 담은 <code>REST_INFO</code> 테이블입니다. <code>REST_INFO</code> 테이블은 다음과 같으며 <code>REST_ID</code>, <code>REST_NAME</code>, <code>FOOD_TYPE</code>, <code>VIEWS</code>, <code>FAVORITES</code>, <code>PARKING_LOT</code>, <code>ADDRESS</code>, <code>TEL</code>은 식당 ID, 식당 이름, 음식 종류, 조회수, 즐겨찾기수, 주차장 유무, 주소, 전화번호를 의미합니다.</p>
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<table class="table">
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<thead><tr>
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<th>Column name</th>
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<th>Type</th>
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<th>Nullable</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>REST_ID</td>
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<td>VARCHAR(5)</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>REST_NAME</td>
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<td>VARCHAR(50)</td>
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<td>FALSE</td>
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</tr>
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<tr>
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<td>FOOD_TYPE</td>
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<td>VARCHAR(20)</td>
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<td>TRUE</td>
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</tr>
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<tr>
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<td>VIEWS</td>
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<td>NUMBER</td>
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<td>TRUE</td>
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</tr>
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<tr>
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<td>FAVORITES</td>
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<td>NUMBER</td>
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<td>TRUE</td>
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</tr>
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<tr>
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<td>PARKING_LOT</td>
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<td>VARCHAR(1)</td>
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<td>TRUE</td>
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</tr>
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<tr>
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<td>ADDRESS</td>
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<td>VARCHAR(100)</td>
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<td>TRUE</td>
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</tr>
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<tr>
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<td>TEL</td>
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<td>VARCHAR(100)</td>
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<td>TRUE</td>
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</tr>
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</tbody>
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</table>
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<hr>
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<h5>문제</h5>
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<p><code>REST_INFO</code> 테이블에서 음식종류별로 즐겨찾기수가 가장 많은 식당의 음식 종류, ID, 식당 이름, 즐겨찾기수를 조회하는 SQL문을 작성해주세요. 이때 결과는 음식 종류를 기준으로 내림차순 정렬해주세요.</p>
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<hr>
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<h5>예시</h5>
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<p><code>REST_INFO</code> 테이블이 다음과 같을 때</p>
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<table class="table">
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<thead><tr>
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<th>REST_ID</th>
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<th>REST_NAME</th>
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<th>FOOD_TYPE</th>
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<th>VIEWS</th>
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<th>FAVORITES</th>
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<th>PARKING_LOT</th>
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<th>ADDRESS</th>
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<th>TEL</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>00001</td>
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<td>은돼지식당</td>
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<td>한식</td>
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<td>1150345</td>
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<td>734</td>
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<td>N</td>
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<td>서울특별시 중구 다산로 149</td>
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<td>010-4484-8751</td>
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</tr>
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<tr>
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<td>00002</td>
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<td>하이가쯔네</td>
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<td>일식</td>
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<td>120034</td>
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<td>112</td>
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<td>N</td>
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<td>서울시 중구 신당동 375-21</td>
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<td>NULL</td>
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</tr>
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<tr>
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<td>00003</td>
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<td>따띠따띠뜨</td>
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<td>양식</td>
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<td>1234023</td>
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<td>102</td>
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<td>N</td>
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<td>서울시 강남구 신사동 627-3 1F</td>
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<td>02-6397-1023</td>
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</tr>
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<tr>
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<td>00004</td>
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<td>스시사카우스</td>
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<td>일식</td>
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<td>1522074</td>
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<td>230</td>
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<td>N</td>
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<td>서울시 서울시 강남구 신사동 627-27</td>
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<td>010-9394-2554</td>
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</tr>
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<tr>
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<td>00005</td>
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<td>코슌스</td>
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<td>일식</td>
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<td>15301</td>
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<td>123</td>
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<td>N</td>
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<td>서울특별시 강남구 언주로153길</td>
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<td>010-1315-8729</td>
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</tr>
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</tbody>
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</table>
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<p>SQL을 실행하면 다음과 같이 출력되어야 합니다.</p>
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<table class="table">
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<thead><tr>
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<th>FOOD_TYPE</th>
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<th>REST_ID</th>
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<th>REST_NAME</th>
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<th>FAVORITES</th>
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</tr>
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</thead>
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<tbody><tr>
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<td>한식</td>
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<td>00001</td>
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<td>은돼지식당</td>
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<td>734</td>
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</tr>
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<tr>
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<td>일식</td>
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<td>00004</td>
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<td>스시사카우스</td>
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<td>230</td>
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</tr>
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<tr>
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<td>양식</td>
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<td>00003</td>
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<td>따띠따띠뜨</td>
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<td>102</td>
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</tr>
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</tbody>
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</table>
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> 출처: 프로그래머스 코딩 테스트 연습, https://school.programmers.co.kr/learn/challenges
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-- 코드를 입력하세요
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SELECT
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food_type,
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rest_id,
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rest_name,
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favorites
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from rest_info
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where (food_type, favorites) in (
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select food_type, max(favorites)
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from rest_info
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group by food_type
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)
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order by food_type desc;

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