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Awkwardly placed comma #10

@teepeemm

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@teepeemm

{$\ds y'=\frac2y$,\qquad $y(0) = 1$

This isn't technically a mistake, but \ds\frac2y, looks very similar to \ds\frac2{y'}. I'm going to try \ds\frac2y; and change to semicolons for the adjacent problems.

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